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20 Mar 2015, 07:23
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A
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Difficulty:
5%
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Question Stats:
83% (01:19) correct
17%
(01:46)
wrong
based on 269
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The length and width of a rectangular yard are 11 meters and 5 meters respectively. If each dimension were reduced by x meters to make the ratio of length to width 8 to 3, what would be the value of x?
A. 1.4
B. 1.6
C. 1.8
D. 2.0
E. 2.2
A. 1.4
B. 1.6
C. 1.8
D. 2.0
E. 2.2
20 Mar 2015, 08:19
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L = 11 meters.
W = 5 meters.
Current ratio of L/W = 11/5. We want to subtract x from both of these values to get a new ratio of 8/3.
\(\frac{11-x}{5-x} = \frac{8}{3}\)
\(3(11-x) = 8(5-x)\)
\(33 - 3x = 40 - 8x\)
\(5x = 7\)
\(x = \frac{7}{5} = 1.4\)
Answer: A
W = 5 meters.
Current ratio of L/W = 11/5. We want to subtract x from both of these values to get a new ratio of 8/3.
\(\frac{11-x}{5-x} = \frac{8}{3}\)
\(3(11-x) = 8(5-x)\)
\(33 - 3x = 40 - 8x\)
\(5x = 7\)
\(x = \frac{7}{5} = 1.4\)
Answer: A
20 Mar 2015, 09:25
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Bunuel
hi,
again a different approach is substituting values after understanding the properties of number...
1) the initial value or ratio is 11:5... if we subtract a value x from the two values ratio becomes 8:3..
2) the above point tells us that 11-x should be multiple of 8 and 5-x should be a multiple of 5....
now lets look at the choice..
A. 1.4
110-14=96 is multiple of 8 and 50-14=36, which is multiple of 3..so this is what we are looking for.. ans
lets look at other choices also
B. 1.6
110-16=94 is not a multiple of 8 and 50-16=34, not a multiple of 3..so this is not what we are looking for
C. 1.8
110-18=92 is not a multiple of 8 and 50-18=32, not a multiple of 3..so this is not what we are looking for
D. 2.0
110-20=90 is not a multiple of 8 although 50-20=30, a multiple of 3..so this is not what we are looking for
E. 2.2
110-22=88 is a multiple of 8 but 50-22=28, not a multiple of 3..so this is not what we are looking for
ans A
