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Bunuel
In the xy-coordinate system, line k has y-intercept 12 and an x-intercept greater than zero. If the area of the triangular region enclosed by line k and the two axes is 30, what is the slope of line k?

A. -12/5
B. -6/5
C. 6/5
D. 3/2
E. 12/5

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Area of triangle = 1/2 (b)(h)

From the prompt, we know 30 = (1/2)(b)(12) --> Solve: b = 5

Coordinates of b = (5,0) & Coordinates of h = (12,0) --> Use slope formula --> [12-0]/[0-5] = -12/5

A
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Equation: y=mx+b, Y-intercept (b) is 12, solving for x-intercept, 0=mx+12, -12/m=x. Given that x>0, therefore 'm' has to be negative. Option A & B alone satisfy the condition.

Substituting m=-12/5, we get x=5. Therefore the two points are (5,0) & (12,0), plotting the points we can see that the area would be 30.
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