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Bunuel
Attachment:
circle_703.png
Each circle has center O. The radius of the smaller circle is 2 and the radius of the larger circle is 6. If a point is selected at random from the larger circular region, what is the probability that the point will lie in the shaded region?

A. 1/9
B. 1/6
C. 2/3
D. 5/6
E. 8/9

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Area of the whole circle=6*6(pi)

Area of the shaded region=36(pi)-4(pi)=32(pi)

Probability=32/36=8/9

Hence E
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Area of larger circle = pi*(6)^2
Are of Smaller circle = pi*(2)^2
Area of Shaded region ==> Area of larger circle - Area of smaller circle
pi(36-4)

Probability of the point being in shaded region = Ar of shaded region/Ar of Larger circle
==> 32pi/36pi = 8/9
Ans E
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Answer = E= 8/9

Area of big circle \(= \pi6^2 = 36\pi\)

Area of shaded region \(= 36\pi - 4\pi = 32\pi\)

Probability \(= \frac{32\pi}{36\pi} = \frac{8}{9}\)
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Bunuel
Attachment:
circle_703.png
Each circle has center O. The radius of the smaller circle is 2 and the radius of the larger circle is 6. If a point is selected at random from the larger circular region, what is the probability that the point will lie in the shaded region?

A. 1/9
B. 1/6
C. 2/3
D. 5/6
E. 8/9

Kudos for a correct solution.

Probability of lying inside the shaded region = Area of Shaded region/Area of the larger circle

= Pi*(6^2 - 2^2)/Pi*6^2

= 32/36

= 8/9

Option E
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Probability of the fact that the point lies in one of the sections is equal to the relation of the areas of the aforementioned section and the area of the whole thing, thus it has to be the relation of the shaded part's area to the whole area, which is easily found as \(\frac{(36-4)\pi}{(36\pi)} = 8/9\)
E
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Big circle radius: 6
Small circle radius: 2

Area big circle: 6^2 = 36
Area small circle: 2^2 = 4

36 - 4 = 32
32 / 36 =
8 / 9
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Bunuel
Attachment:
The attachment circle_703.png is no longer available
Each circle has center O. The radius of the smaller circle is 2 and the radius of the larger circle is 6. If a point is selected at random from the larger circular region, what is the probability that the point will lie in the shaded region?

A. 1/9
B. 1/6
C. 2/3
D. 5/6
E. 8/9

Kudos for a correct solution.

MAGOOSH OFFICIAL SOLUTION:
Attachment:
Target_Probability.png
Target_Probability.png [ 23.33 KiB | Viewed 16821 times ]
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