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Difficulty:
55%
(hard)
Question Stats:
71% (03:17) correct
29%
(03:08)
wrong
based on 347
sessions
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During a trip, Yogi Bear traveled 62.5% of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of \(x\) miles per hour. In terms of \(x\), what was Yogi Bear's average speed for the entire trip?
A. \(\frac{{320x}}{{3+200x}}\)
B. \(\frac{{x+80}}{{120x}}\)
C. \(\frac{{320x}}{{5x+120}}\)
D. \(\frac{{320x+5}}{{200x}}\)
E. \(\frac{{120x}}{{x+80}}\)
Again, from OG 13 with different conditions.
A. \(\frac{{320x}}{{3+200x}}\)
B. \(\frac{{x+80}}{{120x}}\)
C. \(\frac{{320x}}{{5x+120}}\)
D. \(\frac{{320x+5}}{{200x}}\)
E. \(\frac{{120x}}{{x+80}}\)
Again, from OG 13 with different conditions.
09 Aug 2015, 20:42
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I think question have some discrepancy.
the answer for the question is 320x/5x+120.
So, the given option C is 320x/3x+200. It happens only first 62.5% distance covered for xmiles/hour and remaining distance 37.5%
covered by 40 miles/hours.
Average speed of first distance m covered for phours and remaining distance n covered for q hours.
given by the formula.
= (m+n)pq/mq+np.
from given question is
= m+n= 100% distance
=40x/67.5%*x+37.5%*40
=40x/5x/8+15
=320x/5x+120.
suppose there is interchange in distance or speed then
=40x/3x/8+25=320x/3x+200
the answer for the question is 320x/5x+120.
So, the given option C is 320x/3x+200. It happens only first 62.5% distance covered for xmiles/hour and remaining distance 37.5%
covered by 40 miles/hours.
Average speed of first distance m covered for phours and remaining distance n covered for q hours.
given by the formula.
= (m+n)pq/mq+np.
from given question is
= m+n= 100% distance
=40x/67.5%*x+37.5%*40
=40x/5x/8+15
=320x/5x+120.
suppose there is interchange in distance or speed then
=40x/3x/8+25=320x/3x+200
General Discussion
