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If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

Let us consider we have only 2s in the series, then we have 62 "2s" in total.(62 is not there in the options)

To include a 24 in the series we have to take out 12 "2s".
Including one 24 in the series, we have = 62-12 = 50 "2s" (50 is not there in the options)
Including two 24s in the series, we have = 62-12-12 = 38 "2s" (38 is not there in the options)
Including three 24s in the series, we have = 62-12-12-12 = 26 "2s" (26 is there in the options)

Ans:A
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Possible number of "2s" in the series?
2x+24y=124
Find x
testing out the choices, only 26×2 + 24×3 =124

Answer: A. 26
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

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Using the given options,
If no of 2's are 29, then sum of 2's=58 and sum of 24's left=124-58=66 which is not possible
If no of 2's=35, then sum of 2's =70 and sum of 24's left=124-70=54 which is not possible
If no of 2's=26, then sum of 2's=52 and sum of 24's left=124-52=72 which is divisible by 24
Answer A
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substituted the value as 2..gives 2*26 =52 --> which leaves us with 72.. which in turn is divisible by 24
so :A
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

Kudos for a correct solution.


Testing of the options is the easiest in my opinion

A - 26*2 = 52, 124-52 = 72 --> divisible by 24
B,C,D,E leave values of 46, 54, 44, and 28 respectively which are not divisible by 24

So answer is A.
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

We can create the following equation in which a = the number of 2s and b = the number of 24s:

2a + 24b = 124

a + 12b = 62

12b = 62 - a

b = (62 - a)/12

Since 62 - a must be a multiple of 12, a could be 2, 14, 26, 38, or 50. Of the answer choices, 26 is the only value listed.

Answer: A
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2x + 24 y = 124
2(x+12y) = 124
x + 12y = 62

Now let's do process elimination

If x is 26, then
26 + 12 y = 62
12 y = 62 - 26
y = 3

If you try the other answers, you would realize that those numbers will not result an integer.
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The MAX number of "24" that can be in the series is 5, since 24*5 = 120, and thus the number of "2" would then be 2, since 2*2 = 4, and further 120 + 4 = 124. BUT 2 is not one of the options so that can't be correct.

Lets try 3 "24".
24 * 3 = 72.
124 - 72 = 52
52 / 2 = 26 ---> This is the number of "2" that can be in a series with 3 "24"

26 is option A, thus we have our answer.
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