Last visit was: 25 Apr 2026, 06:12 It is currently 25 Apr 2026, 06:12
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,828
Own Kudos:
811,173
 [1]
Given Kudos: 105,878
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,828
Kudos: 811,173
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,048
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,048
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Mo2men
Joined: 26 Mar 2013
Last visit: 09 May 2023
Posts: 2,426
Own Kudos:
1,508
 [2]
Given Kudos: 641
Concentration: Operations, Strategy
Schools: Erasmus (II)
Products:
Schools: Erasmus (II)
Posts: 2,426
Kudos: 1,508
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,048
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Mo2men,

You bring up a very good point. Whoever wrote the answer choices to this question really made it 'easy' for you to spot that pattern. However, you will likely NOT have it so easy on the multi-shape Geometry question(s) that you face on the Official GMAT. Those questions can be some of the most time-consuming and toughest questions that you face. As such, you'll still need to be practicing the proper math 'skills' and Tactics to consistently score at a high level in the Quant section.

GMAT assassins aren't born, they're made,
Rich
User avatar
TeamGMATIFY
Joined: 20 Aug 2015
Last visit: 31 Oct 2016
Posts: 339
Own Kudos:
1,527
 [1]
Given Kudos: 10
Location: India
GMAT 1: 760 Q50 V44
Expert
Expert reply
GMAT 1: 760 Q50 V44
Posts: 339
Kudos: 1,527
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

What is the area of the shaded portion of this rectangle, given that AD = 6, CD = 8, and AE = x?

A. 48 − 3x
B. 48 + 3x
C. 3x + 16
D. 24 − 3x
E. 24 + 3x

Attachment:
2016-01-31_1801.png

Whenever you see a question with shaded area, try to find out the area of the participating figures.
In this case, we need the area of the rectangle ABCD and triangle ADE

1. Area of rectangle = AD*CD = 6*8 = 48
2. Area of triangle = \(\frac{1}{2}\)* AD*AE = \(\frac{1}{2}\) *6*x = 3x

Area of shaded region = area of rectangle - area of triangle = 48 - 3x (Option A)
User avatar
davedekoos
Joined: 09 Jul 2013
Last visit: 07 Nov 2025
Posts: 96
Own Kudos:
347
 [1]
Given Kudos: 11
Posts: 96
Kudos: 347
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The solutions above are perfect, and probably the easiest way to go. I agree with Rich that on the actual test you're probably not going to be so lucky as to see answer choices as straightforward as these.

Another approach would be to calculate the area of the shaded region directly using the formula for the area of a trapezoid.

\(A=\frac{l_1+l_2}{2}*h\) where \(l_1\) and \(l_2\) are the lengths of the parallel sides, and \(h\) is the height (perpendicular distance between the parallel sides)

\(A=\frac{8+(8-x)}{2}*6\)

\(A=(8-\frac{x}{2})*6\)

\(A = 48-3x\)

Answer: A
avatar
sharmilaz87
Joined: 04 May 2015
Last visit: 10 Jul 2016
Posts: 5
Own Kudos:
Given Kudos: 1
Posts: 5
Kudos: 7
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Area of the rectangle ABCD=6*8=48
Let AE=x, since AB=8, EB=8-x
EBCD is a trapezoid
Area of EBCD=(Base1+Base2)/2 * Height={8+(8-x)}/2 * 6=48-3x
Ans.A
User avatar
Sr1994
User avatar
Retired Moderator
Joined: 28 Nov 2019
Last visit: 27 Oct 2025
Posts: 207
Own Kudos:
Given Kudos: 89
Location: India
Schools: ISB '24 Imperial
Schools: ISB '24 Imperial
Posts: 207
Kudos: 251
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Area of shaded portion = Total area - Area of triangle AED

Total area = 6 * 8 = 48

Area of Triangle AED = \(\frac{1}{2}\) * x * 6 = 3X

Therefore , area of shaded portion = 48 - 3X

Answer A
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 24 Apr 2026
Posts: 22,286
Own Kudos:
26,535
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,286
Kudos: 26,535
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

What is the area of the shaded portion of this rectangle, given that AD = 6, CD = 8, and AE = x?

A. 48 − 3x
B. 48 + 3x
C. 3x + 16
D. 24 − 3x
E. 24 + 3x

Attachment:
2016-01-31_1801.png
Solution:

We see that the area of the shaded region is the difference between the area of rectangle ABCD and the area of triangle ADE.

Since the area of rectangle ABCD is 8 * 6 = 48 and the area of triangle ADE is ½ * 6 * x = 3x, the area of the shaded region is 48 - 3x.

Answer: A
Moderators:
Math Expert
109827 posts
Tuck School Moderator
852 posts