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13 Mar 2016, 05:43
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (01:37) correct
22%
(02:00)
wrong
based on 176
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How many different 4-digit numbers can be written using the digits 1 to 8 without repetition such that the number always contains the digit 2?
A. 360
B. 560
C. 760
D. 840
E. 1260
A. 360
B. 560
C. 760
D. 840
E. 1260
13 Mar 2016, 05:52
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chetan2u
The most restrictive case. We should have a two.
No repetition. Numbers range from 1 to 8.
= 1*7*6*5 = 210 ways we can write if '2' is in the first position.
= 4*(210)
=840 ways.
Another method.
Without restriction for 8 digits- 8*7*6*5 = 1680 Ways we can write.
Without restriction for 7 digits- 7*6*5*4 = 840 Ways.
With restriction = 1680 - 840 = 840 Ways.
IMO.D.
