Last visit was: 22 Apr 2026, 11:57 It is currently 22 Apr 2026, 11:57
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,751
Own Kudos:
Given Kudos: 105,821
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,751
Kudos: 810,648
 [19]
1
Kudos
Add Kudos
18
Bookmarks
Bookmark this Post
avatar
ronny123
Joined: 12 Jun 2015
Last visit: 16 Oct 2017
Posts: 69
Own Kudos:
80
 [1]
Given Kudos: 104
Products:
Posts: 69
Kudos: 80
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
HARRY113
Joined: 06 Aug 2015
Last visit: 15 May 2025
Posts: 55
Own Kudos:
65
 [2]
Given Kudos: 84
Concentration: General Management, Entrepreneurship
GMAT Date: 10-30-2016
GRE 1: Q160 V135
GPA: 3.34
WE:Programming (Computer Software)
Products:
GRE 1: Q160 V135
Posts: 55
Kudos: 65
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ynk
Joined: 18 Aug 2013
Last visit: 02 Nov 2017
Posts: 106
Own Kudos:
131
 [1]
Given Kudos: 127
Location: India
Concentration: Operations, Entrepreneurship
GMAT 1: 640 Q48 V28
GPA: 3.92
WE:Operations (Transportation)
GMAT 1: 640 Q48 V28
Posts: 106
Kudos: 131
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Good one.

You don't have to do any calculations for this one.Just see the no. of drivers who said that they encountered 0,1,2 no. of accidents.Its hunge as compared to all others.Hence,the answer will be less than 2 but more than 1.
And since here the choices are quite easy,the answer is C i.e 1.5.
avatar
coolnaren
Joined: 11 Apr 2014
Last visit: 26 Aug 2021
Posts: 17
Own Kudos:
Given Kudos: 37
Posts: 17
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
good one. This is kind of an illusion. Helps to clear the basics
User avatar
aat1
Joined: 26 Oct 2024
Last visit: 20 Jan 2025
Posts: 2
Own Kudos:
1
 [1]
Given Kudos: 3
Posts: 2
Kudos: 1
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Isn't the table showing the accidents over 5 years? If yes, shouldn't the avg be 1.5/5?
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 22 Apr 2026
Posts: 109,751
Own Kudos:
810,648
 [1]
Given Kudos: 105,821
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,751
Kudos: 810,648
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
aat1


The table shows the results of a poll which asked drivers how many accidents they had had over the previous 5 years. What is the median number of accidents per year?

A. 0.5
B. 1
C. 1.5
D. 2
E. 4

Isn't the table showing the accidents over 5 years? If yes, shouldn't the avg be 1.5/5?

We are not asked to find the average per year; we are asked to find the median, which is simply the middle value for an odd number of terms, or the average of the two middle terms for an even number of terms, when the terms are arranged in order.
User avatar
aat1
Joined: 26 Oct 2024
Last visit: 20 Jan 2025
Posts: 2
Own Kudos:
Given Kudos: 3
Posts: 2
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Alright, but the table is giving numbers for 5 years, now the median for each year can be different right? As in, there can be a case where most off the accidents happened in the last year so the median for each of the years (1-5) would be different. So either we take it as an average of 5 years or wouldn't the info be insufficient for this question?
Bunuel
aat1


The table shows the results of a poll which asked drivers how many accidents they had had over the previous 5 years. What is the median number of accidents per year?

A. 0.5
B. 1
C. 1.5
D. 2
E. 4

Isn't the table showing the accidents over 5 years? If yes, shouldn't the avg be 1.5/5?

We are not asked to find the average per year; we are asked to find the median, which is simply the middle value for an odd number of terms, or the average of the two middle terms for an even number of terms, when the terms are arranged in order.
User avatar
Suriya28
Joined: 01 Nov 2024
Last visit: 19 Apr 2026
Posts: 12
Given Kudos: 26
Posts: 12
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Total Number of Drivers : 17 +13 + 21 + 4 + 2 + 2 + 1 = 60
So, the median number of accidents per year should be between the 30th and the 31st driver
The 30th driver had committed 1 accident
The 31st driver had committed 2 accidents

The median = 1+2 /2 = 1.5 accidents per year

Option C
Moderators:
Math Expert
109751 posts
Tuck School Moderator
853 posts