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A machine puts c caps on bottles in m minutes.
So, the machine puts 1 cap in m/c minutes

To put caps on b bottles, the machine will take bm/c minutes
In order to calculate the no. of hours taken , divide the product by 60.
So, our answer is bm/60c

Answer : B
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The key for me is to realise that 1 bottle can only have 1 cap.
(ie bottles can be multiplied with minutes/cap and cancel out leaving only time)

Without that it seems super difficult but actually is a very straightforward calculation.
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We can plug in simple numbers

2 caps per 1 min,, then rate= 2 caper/min

Put b= 120 or 60 bottles.. I used 120 bottles

120= 2 * t.....>t=60 min =1 hr

Scanning the answer choice.. Eliminate A & D as you need to divide minute by 60.
Eliminate E as CM should be together.

Substitute number in choice B & C

In bm/60c= (120*1)/ (2 *60) = 1

Answer: B
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Bunuel
A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c
B. bm/60c
C. bc/60m
D. 60b/cm
E. b/60cm

A machine puts c caps on bottles in M minutes. A bottle can only have 1 cap, so this means that in M minutes, the machine will cap C bottles

\(\frac{M minutes}{C bottles}\)

How many hours will it take to put caps on B bottles? This is a comparison ratio:

\(\frac{M minute}{C bottles}\) * \(\frac{1 hour}{60 minutes}\) = \(\frac{X hours}{B bottles}\)

This becomes:

\(\frac{(M minute)(B bottles)(1 hour)}{(C bottles)(60 minutes)}\) = \(x hours\)

Simplify to:

\(\frac{mb}{60c}\) = \(x hours\)

This question's only difficulty is seeing that they want you to do a comparison between c bottles and b bottles. They intentionally made the letters confusing for those that could only see b should stand for bottles.
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chiccufrazer1
A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c
B. bm/60c
C. bc/60m
D. 60b/cm
E. b/60cm

bottling rate=c/m
minutes to cap b bottles=b/(c/m)=bm/c
hours to cap b bottles=(bm/c)/60=bm/60c
B
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Rate Time = Work
C/M M C

C/M x = B

So, (RT = W); X*C/M = B; BM/C this is in Hours, therefore BM/C/60= BM/C60
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Bunuel
A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c
B. bm/(60c)
C. bc/(60m)
D. 60b/(cm)
E. b/(60cm)

my approach:

we have : c caps --> m minutes
therefore b caps --> \(\frac{(b*m)}{c}\) minutes

And : 60 minutes = 1 hour
so: \(\frac{(b*m)}{c}\) minutes = \(\frac{(b*m)}{(c*60)}\) hours

Answer: B.
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rate of caps on bottles in per m minute ; c/m
and in 1 hour caps being put on bottles at given rate ; c*60/m
w = r*t
b = c*60/m * t
t = bm/60c
option B

Abhii46
A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?

A. 60bm/c
B. bm/(60c)
C. bc/(60m)
D. 60b/(cm)
E. b/(60cm)
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