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Bunuel
In the following sequence: [x, y, z, 5, 7, 16, 28] each number is equal to the sum of the three numbers preceding it. What is x+y?

A. -5
B. -1
C. 1
D. 5
E. 6

16= 7+5+z or
z=4

7=y+z+5 or
7=y+4+5 or
y=-2

5=x+y+z or
5=4-2+x or
x=3

x+y=1

Answer - C
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Bunuel
In the following sequence: [x, y, z, 5, 7, 16, 28] each number is equal to the sum of the three numbers preceding it. What is x+y?

A. -5
B. -1
C. 1
D. 5
E. 6

z= 16- (5+7)= 4

y= 7 -( 5+4=)= -2

x= 5- (4-2)= 3

x+y= 3-2= 1

C is the answer
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From the sequence it is clear that 5=x+y+z or x+y=5-z...........(1)
We only need the value of z

16=7+5+z; hence, z=4

Substituting value of z in (1), x+y = 1
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