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We can calculate the equation of line k, since we know that the slope is (-3/5) and passes through the point (6,2)

Substituting we have:
Y=(-3/5)X+Z
2=(-3/5)*6+Z

Z=(28/5)
Therefore we have eq.1= Y=(-3/5)x+(28/5)

Equation 2 is easier because we know that the slope is -2 and passes through the origin, so eq. 2 would be:
Y=-2X

No need of calculation here.

We substitute eq.1 in eq.2 to see where do they intersect:
-2x=(-3/5)x+(28/5)

We get x=-4 y=8, answer B
Thank you.
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AbdurRakib
Line k passes through the points (6,2) and P and has a slope of \(\frac{−3}{5}\) . If the line that passes through the origin and point P has a slope of –2, which of the following are the xy-coordinates for point P ?

A. (\(\frac{-40}{7}\),\(\frac{80}{7}\))
B. (-4,8)
C. (-3,6)
D. (\(\frac{11}{5}\),\(\frac{-22}{5}\))
E. (\(\frac{28}{13}\),\(\frac{-56}{13}\))

y-2/x-6 = -3/5 ....1

y =-2x ......2

on solving 1 and 2 we get x=-4 and y=8

THerefore IMO B
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