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Updated on: 13 May 2017, 07:54
Originally posted by GMATinsight on 13 May 2017, 05:59.
Last edited by Bunuel on 13 May 2017, 07:54, edited 1 time in total.
Last edited by Bunuel on 13 May 2017, 07:54, edited 1 time in total.
Edited the OA.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (01:30) correct
18%
(01:40)
wrong
based on 376
sessions
History
Date
Time
Result
Not Attempted Yet
What is the number of solutions of the equation 2x + y = 40 where x and y are both positive Integers?
A) 7
B) 13
C) 14
D) 18
E) 19
A) 7
B) 13
C) 14
D) 18
E) 19
13 May 2017, 07:11
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GMATinsight
Hi
Again wrong OA..
Ans is E and not B
X and y are POSITIVE so >0..
2x+y=40..
x can take any value from 1 to 19.. as soon as x is 20, y becomes 0..
So solutions are 19..
(x, y) can be (1,38);(2,36);(3,34)(4,32);(5,30)......(19,2)
So ans is 19
E...
Updated on: 01 Nov 2021, 06:21
Originally posted by BrentGMATPrepNow on 13 May 2017, 08:02.
Last edited by BrentGMATPrepNow on 01 Nov 2021, 06:21, edited 1 time in total.
Last edited by BrentGMATPrepNow on 01 Nov 2021, 06:21, edited 1 time in total.
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GMATinsight
Let's test some possible solutions, starting with the SMALLEST possible value of x.
1) x = 1 and y = 38
2) x = 2 and y = 36
3) x = 3 and y = 34
4) x = 4 and y = 32
.
.
.
We can see that, for each integer x-value, there is an integer value of y that completes the equation 2x + y = 40
How big can the x-value get?
The biggest possible x-value is 19. Once we get to x = 20, then y = 0, and y is not positive.
.
.
.
19) x = 19 and y = 2
STOP!
Answer: E
Cheers,
Brent
