In sequence S, all odd numbered terms are equal and all even numbered

Question

In sequence S, all odd numbered terms are equal and all even numbered terms are equal. The first term in the sequence is \(\sqrt{2}\) and the second term is –2. What is approximately the sum of two consecutive terms of the sequence?

(A) –2
(B) –0.6
(C) 0
(D) 2
(E) 0.8

(A) –2 
(B) –0.6 
(C) 0 
(D) 2 
(E) 0.8

Bunuel · Answer

\sqrt{2} \approx 1.4 , thus the sum of two consecutive terms of the sequence  \approx 1.4 - 2 = -0.6 .

Answer: B.

sashiim20 · Answer

In sequence S, all odd numbered terms are equal and all even numbered terms are equal. The first term in the sequence is \(\sqrt{2}\) and the second term is –2. What is approximately the sum of two consecutive terms of the sequence?

Since its mentioned in the question all odd numbered terms are equal and all even numbered terms are equal.
All odd numbered terms = \(\sqrt{2}\)
[\(\sqrt{2}\) = 1.4 (approximately)]
All even numbered terms = -2
Therefore sum of consecutive terms = \(\sqrt{2}\) + (-2) = \(\sqrt{2}\) - 2
Required sum = 1.4 - 2 = - 0.6 ... Answer B.....

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BrentGMATPrepNow · Answer

A small note concerning the approximate values of some roots (as the 2 posters above have noted).

On the GMAT, it is very useful to memorize the following approximations:

√2 ≈ 1.4
√3 ≈ 1.7
√5 ≈ 2.2

Cheers,
Brent

EMPOWERgmatRichC · Answer

Hi rohan2345,

While the answer choices might look "close" to one another, they're sufficiently 'spaced out' that you really don't need to do much math to answer this question.

To start, you probably know a couple of simple square roots already:

\sqrt{1} = 1 
 \sqrt{4} = 2

So we know that  \sqrt{2}  is BETWEEN 1 and 2. This question asks us to subtract 2 from  \sqrt{2} , so we're ultimately looking for an answer that is between -1 and 0... There's only one answer that fits...

Final Answer:  B 
 
GMAT assassins aren't born, they're made,
Rich

In sequence S, all odd numbered terms are equal and all even numbered

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