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C
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Difficulty:
5%
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Question Stats:
84% (00:33) correct
16%
(00:37)
wrong
based on 179
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The number of integers from 2 to 10^3 , inclusive is
(A) 997
(B) 998
(C) 999
(D) 1000
(E) 1001
(A) 997
(B) 998
(C) 999
(D) 1000
(E) 1001
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28 May 2017, 02:58
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999 if we count for 2 to 10 we have 9 integers i.e 10-1 hence for 10^3 it would be 1000-1 = 999
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Sent from my iPhone using GMAT Club Forum
28 May 2017, 03:00
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The number of integers between any 2 numbers, both inclusive is given by :
If a and b are the two integers, # of integers is a-b+1.
Hence the number of integers between 2 to 1000(10^3) is 1000-2+1 = 999(Option C)
If a and b are the two integers, # of integers is a-b+1.
Hence the number of integers between 2 to 1000(10^3) is 1000-2+1 = 999(Option C)
