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01 Jun 2017, 13:52
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C
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Difficulty:
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Question Stats:
97% (00:53) correct
3%
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wrong
based on 112
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\(\frac{v + w}{(\frac{x}{yz})}\)
To halve the value of the expression above by doubling exactly one of the variables, one must double which of the following variables?
(A) v
(B) w
(C) x
(D) y
(E) z
To halve the value of the expression above by doubling exactly one of the variables, one must double which of the following variables?
(A) v
(B) w
(C) x
(D) y
(E) z
01 Jun 2017, 14:04
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We are given the expression \(\frac{v + w}{(\frac{x}{yz})}\)
Since we have to halve the value of this expression by doubling
exactly one of the variables, we must double the value of x.
By doing this, the expression becomes \(\frac{v + w}{(\frac{2x}{yz})}\)
This is nothing but \(\frac{1}{2}\)*\(\frac{v + w}{(\frac{x}{yz})}\)(Option C)
Since we have to halve the value of this expression by doubling
exactly one of the variables, we must double the value of x.
By doing this, the expression becomes \(\frac{v + w}{(\frac{2x}{yz})}\)
This is nothing but \(\frac{1}{2}\)*\(\frac{v + w}{(\frac{x}{yz})}\)(Option C)
01 Jun 2017, 15:48
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To halve any expression, we can just double the denominator in the expression. In this case the denominator is \(\frac{x}{yz}\)
To double any expression, the numerator can be multiplied by 2 which is "x" in this case.
Hence we can just double the variable "x" (numerator in the denominator) so option C
To double any expression, the numerator can be multiplied by 2 which is "x" in this case.
Hence we can just double the variable "x" (numerator in the denominator) so option C
