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To halve the value of the expression above by doubling exactly one of

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Bunuel
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To halve the value of the expression above by doubling exactly one of [#permalink] New post   01 Jun 2017, 13:52
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\(\frac{v + w}{(\frac{x}{yz})}\)

To halve the value of the expression above by doubling exactly one of the variables, one must double which of the following variables?

(A) v
(B) w
(C) x
(D) y
(E) z
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C
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pushpitkc
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   01 Jun 2017, 14:04
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We are given the expression \(\frac{v + w}{(\frac{x}{yz})}\)

Since we have to halve the value of this expression by doubling
exactly one of the variables, we must double the value of x.

By doing this, the expression becomes \(\frac{v + w}{(\frac{2x}{yz})}\)
This is nothing but \(\frac{1}{2}\)*\(\frac{v + w}{(\frac{x}{yz})}\)(Option C)
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   01 Jun 2017, 15:48
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To halve any expression, we can just double the denominator in the expression. In this case the denominator is \(\frac{x}{yz}\)

To double any expression, the numerator can be multiplied by 2 which is "x" in this case.

Hence we can just double the variable "x" (numerator in the denominator) so option C
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   02 Jun 2017, 00:06
(v+w)/(x/yz) can be written as:

(v+w)*(yz)/x . Only variable in the denominator is x. if we double that, the expression will become half.
So we need to double x.

Option C answer
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   04 Jun 2017, 12:33
We have

\(\frac{v+w}{1} * \frac{yz}{x}\) => \(\frac{yz (v+w)}{x /2}\) =>\(\frac{2yz(v+w)}{x}\)

The correct answer is Option C .

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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   04 Jun 2017, 12:37
pushpitkc wrote:
We are given the expression \(\frac{v + w}{(\frac{x}{yz})}\)

Since we have to halve the value of this expression by doubling
exactly one of the variables, we must double the value of x.

By doing this, the expression becomes \(\frac{v + w}{(\frac{2x}{yz})}\)
This is nothing but \(\frac{1}{2}\)*\(\frac{v + w}{(\frac{x}{yz})}\)(Option C)


it is X. a simple question
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   04 Jun 2017, 13:28
Rearrange formula to be

((v+w)*yz)/x

Therefore double x
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   05 Jun 2017, 15:49
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Bunuel wrote:
\(\frac{v + w}{(\frac{x}{yz})}\)

To halve the value of the expression above by doubling exactly one of the variables, one must double which of the following variables?

(A) v
(B) w
(C) x
(D) y
(E) z


Observe that (v + w)/(x/yz) = (yz(v + w))/x. We note that if the denominator of a fraction is doubled, then the fraction itself is halved. Thus, we must double x in order to halve the given expression.

Answer: C
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   08 Jul 2018, 05:42
Very well explained!
workout wrote:
To halve any expression, we can just double the denominator in the expression. In this case the denominator is \(\frac{x}{yz}\)

To double any expression, the numerator can be multiplied by 2 which is "x" in this case.

Hence we can just double the variable "x" (numerator in the denominator) so option C
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Re: To halve the value of the expression above by doubling exactly one of [#permalink] New post   31 Jul 2022, 06:38
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Re: To halve the value of the expression above by doubling exactly one of [#permalink]
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