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Bunuel
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(v+w)/(x/yz) can be written as:

(v+w)*(yz)/x . Only variable in the denominator is x. if we double that, the expression will become half.
So we need to double x.

Option C answer
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We have

\(\frac{v+w}{1} * \frac{yz}{x}\) => \(\frac{yz (v+w)}{x /2}\) =>\(\frac{2yz(v+w)}{x}\)

The correct answer is Option C .

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We are given the expression \(\frac{v + w}{(\frac{x}{yz})}\)

Since we have to halve the value of this expression by doubling
exactly one of the variables, we must double the value of x.

By doing this, the expression becomes \(\frac{v + w}{(\frac{2x}{yz})}\)
This is nothing but \(\frac{1}{2}\)*\(\frac{v + w}{(\frac{x}{yz})}\)(Option C)

it is X. a simple question
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Rearrange formula to be

((v+w)*yz)/x

Therefore double x
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Bunuel
\(\frac{v + w}{(\frac{x}{yz})}\)

To halve the value of the expression above by doubling exactly one of the variables, one must double which of the following variables?

(A) v
(B) w
(C) x
(D) y
(E) z

Observe that (v + w)/(x/yz) = (yz(v + w))/x. We note that if the denominator of a fraction is doubled, then the fraction itself is halved. Thus, we must double x in order to halve the given expression.

Answer: C
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Very well explained!
workout
To halve any expression, we can just double the denominator in the expression. In this case the denominator is \(\frac{x}{yz}\)

To double any expression, the numerator can be multiplied by 2 which is "x" in this case.

Hence we can just double the variable "x" (numerator in the denominator) so option C
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