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Bunuel
Due to a 25% increase in the price of diesel, a person got 10 liters less quantity for $50 than he was getting before the increase. What was the initial price per liter of diesel?

(A) $1.00
(B) $1.50
(C) $2.25
(D) $2.50
(E) $3.00

Let the initial price of diesel be \(x\), and initial quantity of diesel be \(y\) liters.

Quantity of diesel bought for \($50 => xy = 50\)-------- (i)

Price increased by \(25\)% = \(125\)% of \(x\) \(= \frac{125}{100} * x = 1.25x\)

Quantity of diesel decreased by \(10\) liters \(= (y - 10)\) liters

Quantity of diesel bought for \($50\) after price increase \(=> 1.25x(y - 10) = 50\) -------- (ii)

Equating (i) and (ii), we get;

\(xy = 1.25x(y - 10)\)

\(xy = 1.25xy - 12.5x\)

\(1.25xy - xy = 12.5x\)

\(0.25xy = 12.5x\)

\(0.25y = 12.5\)

\(y = \frac{12.5}{0.25} = 50\)

Therefore initial quantity of diesel, \(y = 50\) liters.

Substituting value of \(y\) in equation (i), we get Initial price \(x\);

\(xy = 50 =>\)\(x*50 = 50\)

\(x = \frac{50}{50} = 1.\)

Therefore Initial price of diesel \(= $1.00\). Answer (A)...
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Let the initial price be x. New price would be 1.25x . 1.25x should be a perfect divisor of 50. This is true only for option A. Hence, by elimination answer is A.

Time to solve using this method would be 30 sec max.
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\sqrt{}
Bunuel
Due to a 25% increase in the price of diesel, a person got 10 liters less quantity for $50 than he was getting before the increase. What was the initial price per liter of diesel?

(A) $1.00
(B) $1.50
(C) $2.25
(D) $2.50
(E) $3.00


Back solve the question .

A) 1

No of liters of diesel = 50 /1 = 50

After 25% increase = price = 1.25

50 / 1.25 = 40

Difference is 10.

The best answer is A.
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Bunuel
Due to a 25% increase in the price of diesel, a person got 10 liters less quantity for $50 than he was getting before the increase. What was the initial price per liter of diesel?

(A) $1.00
(B) $1.50
(C) $2.25
(D) $2.50
(E) $3.00

Expense = Amount * Price
If price goes up to (5/4) of initial, Amount will go down to (4/5) of initial to keep the expense same.

So this 1/5 reduction is 10 lts which means the initial amount was 5*10 = 50 lts

Initial price of diesel = $50/50 lts = $1/lts

Answer (A)
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present : past =125:100
=5:4
50*25/100 = 12.5/10
one litre price =1.25
past price = 1.25*4/5
=1$
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