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07 Jul 2017, 00:41
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
92% (01:39) correct
8%
(02:52)
wrong
based on 71
sessions
History
Date
Time
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Not Attempted Yet
A certain right circular cylinder has a radius of 5 inches. A certain quantity of liquid fills this cylinder to a height of 9 inches. When all of this liquid is poured into a second right circular cylinder, the liquid fills the second cylinder to a height of 4 inches. What is the radius of the second cylinder, in inches?
(A) 6.0
(B) 6.5
(C) 7.0
(D) 7.5
(E) 8.0
(A) 6.0
(B) 6.5
(C) 7.0
(D) 7.5
(E) 8.0
07 Jul 2017, 02:58
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Bunuel
It should be D.
Lets say first cylinder is has a radius R1 and height h1 while the second cylinder has a height R2 and height h2. Since they both fill the same volume, we can equate their filled areas as equivalent cylinders.
\(πR2^2h2 = πR1^2h1\)
pi is cancelled on each side.
\(R2^2 * 4 = 5^2 * 9\)
\(R2^2 * 4 = 225\)
\(R2^2 = 225/4\)
\(R2 = 15/2\)
which is 7.5 or D
07 Jul 2017, 04:20
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Bunuel
Volume of Liquid in both cylinders is same hence
Volume of first cylinder with height 9 = Volume of first cylinder with height 4
(Pi)r^2*9 = (Pi)r^2*4
5^2*9 = r^2*4
(5^2*9)/4 = r^2
i/.e. r = 15/2
Answer: Option D
