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Bunuel
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Bunuel
If x > y and a > b, which of the following must be true?


A. x > a

B. a > b

C. x + b > y + a

D. x + a > y + b

E. a + b > x + y

Bunuel, I think there is a mistake with the choice B.

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Edited. Thank you.
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Bunuel
If x > y and a > b, which of the following must be true?


A. x > a

B. y > b

C. x + b > y + a

D. x + a > y + b

E. a + b > x + y


Its D becoz it satisfies both integer and fractional values


Its D
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Bunuel
If x > y and a > b, which of the following must be true?


A. x > a

B. y > b

C. x + b > y + a

D. x + a > y + b

E. a + b > x + y

I will go with D

x>y & a>b

All other options are wrong and D makes sense

A Wrong as per the information given
B Wrong as per the information given
C What if x= 4, y=3 & a=-1 and b=-7
D Hold
E What if x=4, y=3 & a=-1 and b=-7
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Bunuel
If x > y and a > b, which of the following must be true?


A. x > a

B. y > b

C. x + b > y + a

D.

E. a + b > x + y


2 inequalities in same direction then we can sum them up

x + a > y + b

Answer: D
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When there is an inequality like x>y, then we can clearly say that x-y > 0
Similarly for the other inequality a>b, we can say the same a-b > 0

Hence, we can come to the conclusion that x+a - (y+b) > 0

This will give x+a > y+b(Option D)
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when the inequalities are in the same direction, we can add it up

hence x+a > y +b

ans D
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