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dramamur
If 4 < x < 100, for how many values of x is \(\frac{x}{4}\) square of an integer?

A. 2
B. 3
C. 4
D. 5
E. 6

\(4 < x < 100\)

Squares between \(4\) and \(100\) are \(= 9, 16, 25, 36, 49, 64, 81\)

Out of the above numbers, numbers that are divisible by \(4 = 16, 36, 64\)

Therefore \(x\) could be \(= 16, 36, 64\)

Checking \(\frac{x}{4}\) is square;

\(\frac{16}{4} = 4 ------ (2^2)\)

\(\frac{36}{4} = 9 ------ (3^2)\)

\(\frac{64}{4} = 16 ------ (4^2)\)

Hence total number of values of \(x\) where \(\frac{x}{4}\) is square of an integer \(= 3\)

Answer (B)...
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4<x<100

[x][/4] = I^2

Therefore, x = 4*I^2

If I = 1

x = 4 (but x>4)

Therefore, I = 2

x = 16

Similarly, x = 36, 64

when I = 5

x = 100 (However, x is less than 100)

Therefore, the only values are 3. x = 16, 36, 64 (I = 2,3,4)
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is it weird that the wording of the question just didnt make sense to me?
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4<x<100;

1<(x/4)<25 (just divide all parts of the inequality by 4).

x/4 should be the square of an integer,
thus x/4 could be 2^2 = 4, 3^2 = 9 or 4^2 = 16 (x could be 16, 36, or 64, respectively).

Answer: B
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