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Out of the given options prime numbers less than 100 can be correct.
99 is not a prime number.
97 can be considered.
option A and B have numbers less than 97 so the answer is C.
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We need to find the biggest prime number which is smaller than 100! and which will divide it to give an integer.

In this case, 97 is that number which when divides 100! will give us an integer (Option C)
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100! * 100! = 1^2 * 2^2 * 3^2 * ..... * 96^2 * 97^2 * 98^2 * 99^2 * 100^2

101 is not possible.
99 is not prime.
Hence largest prime number that is the factor of 100!*100! is 97.

Answer : C
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Bunuel
If n = 100! x 100!, what is the largest value of prime number t, such that n/t is an integer?

A. 7
B. 19
C. 97
D. 99
E. 101

We need to check the max prime no. available in 100! only.
So, it can't be 101 as it is greater than 100
99 is not a prime number.
97 is a prime number

Answer C
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