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Bunuel
If (x+2)^2 = 225, which of the following could be the value of x−2?

A. 15
B. 13
C. -13
D. -17
E. -19

(x+2)^2 = 225
=> x+2 = 15 or x+2 = -15
=> x-2 = 11 or x-2 = -19

Answer E
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Skywalker18
Bunuel
If (x+2)^2 = 225, which of the following could be the value of x−2?

A. 15
B. 13
C. -13
D. -17
E. -19

(x+2)^2 = 225
=> x+2 = 15 or x+2 = -15
=> x-2 = 11 or x-2 = -19

Answer E

How did the number 15 come about?
sorry, I started a study for the GMAt today
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joaolucas193
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Bunuel
If (x+2)^2 = 225, which of the following could be the value of x−2?

A. 15
B. 13
C. -13
D. -17
E. -19

(x+2)^2 = 225
=> x+2 = 15 or x+2 = -15
=> x-2 = 11 or x-2 = -19

Answer E

How did the number 15 come about?
sorry, I started a study for the GMAt today

Hi joaolucas193,

We can write 225 in prime factorization form; \(225=5^2*3^2\)
Now \(\sqrt{{225}}=\sqrt{5^2*3^2}\)=\(\sqrt{5^2}*\sqrt{3^2}\)=\(5*3=15\)
Hope it's clear.
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Bunuel
If (x+2)^2 = 225, which of the following could be the value of x−2?

A. 15
B. 13
C. -13
D. -17
E. -19

Taking the square root of both sides we have:

|x+2| = 15

Because this is an absolute value equation, we must consider 2 different cases to find all possible values of x.

Case 1.Solving for when (x + 2) is positive, we have:

x + 2 = 15

x = 13

Case 2. Solving for when (x + 2) is negative we have:

-(x + 2) = 15

-x - 2 = 15

-x = 17

x = -17

Thus, (x - 2) is either 11 or -19.

Answer: E
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Reminder to keep up those Error logs!

This is what 5 attempts over a month and a half looks like - it ain't much but it is improvement!

" 1st - bad path b/c scared to square
2nd - squared variable forgot negative possibility
3rd - when taking root of squared learned to set expression as absolute value
4th - Properly took absolute value, but didn't solve question asked for (x-2) not x
5th - got it right :) "
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