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SajjadAhmad
If –3 < x < –1 and 3 < y < 7, which of the following best describes \(\frac{x-y}{2}\)
?

(A) −5 < \(\frac{x−y}{2}\) < −2

(B) −3 < \(\frac{x−y}{2}\) < −1

(C) −2 < \(\frac{x−y}{2}\) < 0

(D) 2 < \(\frac{x−y}{2}\) < 5

(E) 3 < \(\frac{x−y}{2}\) < 7

Source: Nova GMAT
Difficulty Level: 600

Asked: If –3 < x < –1 and 3 < y < 7, which of the following best describes \(\frac{x-y}{2}\)
?

-1.5 < x/2 < - .5 (1)
1.5< y/2 <3.5
-1.5 > -y/2 > - 3.5
-3.5 < -y/2 < -1.5 (2)

(1) + (2)
- 5 < (x-y)/2 < -2

IMO A
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If –3 < x < –1 and 3 < y < 7, which of the following best describes \(\frac{x-y}{2}\)
?

(A) −5 < \(\frac{x−y}{2}\) < −2

(B) −3 < \(\frac{x−y}{2}\) < −1

(C) −2 < \(\frac{x−y}{2}\) < 0

(D) 2 < \(\frac{x−y}{2}\) < 5

(E) 3 < \(\frac{x−y}{2}\) < 7

Source: Nova GMAT
Difficulty Level: 600


The subtractions are : -6, -8, -10, -4
so, 10<x-y<-4
−5 < \(\frac{x−y}{2}\) < −2

The Answer will A.
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Sajjad1994
If –3 < x < –1 and 3 < y < 7, which of the following best describes \(\frac{x-y}{2}\)
?

(A) −5 < \(\frac{x−y}{2}\) < −2

(B) −3 < \(\frac{x−y}{2}\) < −1

(C) −2 < \(\frac{x−y}{2}\) < 0

(D) 2 < \(\frac{x−y}{2}\) < 5

(E) 3 < \(\frac{x−y}{2}\) < 7

Solution:

If x = -3 and y = 7, then (x - y)/2 = (-3 - 7)/2 = -5. However, since x is greater than -3 and y is less than 7, we see that (x - y)/2 is actually greater than -5.

Similarly, if x = -1 and y = 3, then (x - y)/2 = (-1 - 3)/2 = -2. However, since x is less than -1 and y is greater than 3, then (x - y)/2 is actually less than -2.

Answer: A
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