On a z day hiking trip, 4 children consumed food costing x dollars.

Question

On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z?

A. 4z/(35x)

B. 140z/x

C. 140x/z

D. 28x/(5z)

E. 35x/(4z)

A. 4z/(35x)

B. 140z/x

C. 140x/z

D. 28x/(5z)

E. 35x/(4z)

Luckisnoexcuse · Answer

4 C + Z D = X $
7 C + 5 D = ?? $

1 C + Z D = X/4 $
1 C + 1 D = X/4Z $
7 C + 1 D = 7X/4Z $
7 C + 5 D = 35X/4Z $

E

generis · Answer

Divide total cost by number of children  and  by # of days, because we need cost of food  per  child  per  day from the first scenario to set up the equation for the second scenario.

First scenario:

\frac{Total Cost}{#ofDays}   = how many dollars are available for each day, then

\frac{Amt.One Day}{# children}   = amt. for 1 child for 1 day

Combine them:

Total dollars _______
(# days) * (# children)

x = total dollars for
z = # of days and
4 = # of children

Cost per child per day =

Total dollars (x) ____
(z days) * (4 children)

\frac{x}{4z}  = cost per child per day

Second scenario: Total cost (just reverse operations from first scenario) =
 
(cost per child per day) * (# of days) * (# of children)

So for 5 days and 7 children

\frac{x}{4z}  * 5 * 7 =

\frac{35x}{4z}

ANSWER E

Arsh4MBA · Answer

For z days , total cost for 4 children =x;
For 1 day per child , cost = x/4z;

For 7 children ,cost of food for 5 days = 5*7* x/4z= 35x/4z;

Ans:E

JeffTargetTestPrep · Answer

For the z-day hiking trip, the cost of food per child per day is (x/4)/z = x/(4z). Thus, the total cost of food for 7 children during a 5-day trip is x/(4z) * 7 * 5 = 35x/(4z).

Answer: E

sasyaharry · Answer

4 children - x dollars - Z days

1 child - \frac{x}{4}  dollars - Z days

1 child - \frac{x}{4Z}  dollars - 1 day.

Rate of each child =  \frac{x}{4z}  dollars/day.

For 7 children =  \frac{7x}{4z}  dollars/day

For 5 days =  \frac{35x}{4z}  dollars.

Answer is E.

gps5441 · Answer

If we plugin nos we get 2 answers.
Let z=4 days,y=4 no of children and cost of food=16 dollars
Cost per child=16/4X4=1 dollar

2nd case =1X7X5=35

If we plugin above we get B & D as the correct answer.
My question to the experts is that can we get such kind of questions?

testcracker · Answer

say, cost = c

4z / x = (7*5) / c

or, c = 35x / 4z

thanks

Manick9 · Answer

4 children consumed food worth x amt of money for z days.

7 children would consume (7 * x/4) for z days.
For a 5 day hiking trip, they would consume (5/z * 7x/4) = 35x/4z

Option C.

energetics · Answer

Known: z*4*cost = x 
Unknown: 5*7*cost = ? in terms of x,z

Solving algebraically:  
Given 4zc = x --> c = x/4z
Substitute into 35(c) --> 35(x/4z), E

Plugging in numbers: 
z*4*cost = x 
2*4*10 = 80
35c = 35*10 = 350, this is our target

We can see in the answer choices that 35 is in A) and E) so test first
A) 4*10 / 35*80, no
E) 35*80 / 4*2 --> 35*10 --> 350, yes

A rule of plugging in numbers is to use simple numbers not in the prompt and avoid using 1 and potentially 0

On a z day hiking trip, 4 children consumed food costing x dollars.

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GMAT Problem Solving (PS) Questions

On a z day hiking trip, 4 children consumed food costing x dollars.

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