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• ### $450 Tuition Credit & Official CAT Packs FREE November 15, 2018 November 15, 2018 10:00 PM MST 11:00 PM MST EMPOWERgmat is giving away the complete Official GMAT Exam Pack collection worth$100 with the 3 Month Pack ($299) # On a z day hiking trip, 4 children consumed food costing x dollars.  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: ### Hide Tags Math Expert Joined: 02 Sep 2009 Posts: 50570 On a z day hiking trip, 4 children consumed food costing x dollars. [#permalink] ### Show Tags 07 Sep 2017, 22:28 00:00 Difficulty: 35% (medium) Question Stats: 74% (01:59) correct 26% (02:27) wrong based on 188 sessions ### HideShow timer Statistics On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z? A. 4z/(35x) B. 140z/x C. 140x/z D. 28x/(5z) E. 35x/(4z) _________________ Director Joined: 18 Aug 2016 Posts: 625 Concentration: Strategy, Technology GMAT 1: 630 Q47 V29 GMAT 2: 740 Q51 V38 Re: On a z day hiking trip, 4 children consumed food costing x dollars. [#permalink] ### Show Tags 07 Sep 2017, 22:36 Bunuel wrote: On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z? A. 4z/(35x) B. 140z/x C. 140x/z D. 28x/(5z) E. 35x/(4z) 4 C + Z D = X$
7 C + 5 D = ?? $1 C + Z D = X/4$
1 C + 1 D = X/4Z $7 C + 1 D = 7X/4Z$
7 C + 5 D = 35X/4Z \$

E
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On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

### Show Tags

08 Sep 2017, 09:30
1
Bunuel wrote:
On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z?

A. 4z/(35x)

B. 140z/x

C. 140x/z

D. 28x/(5z)

E. 35x/(4z)

Divide total cost by number of children and by # of days, because we need cost of food per child per day from the first scenario to set up the equation for the second scenario.

First scenario:

$$\frac{Total Cost}{#ofDays}$$ = how many dollars are available for each day, then

$$\frac{Amt.One Day}{# children}$$ = amt. for 1 child for 1 day

Combine them:

Total dollars_______
(# days) * (# children)

x = total dollars for
z = # of days and
4 = # of children

Cost per child per day =

Total dollars (x)____
(z days) * (4 children)

$$\frac{x}{4z}$$ = cost per child per day

Second scenario: Total cost (just reverse operations from first scenario) =

(cost per child per day) * (# of days) * (# of children)

So for 5 days and 7 children

$$\frac{x}{4z}$$ * 5 * 7 =

$$\frac{35x}{4z}$$

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Re: On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

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10 Sep 2017, 19:46
Bunuel wrote:
On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z?

A. 4z/(35x)

B. 140z/x

C. 140x/z

D. 28x/(5z)

E. 35x/(4z)

For z days , total cost for 4 children =x;
For 1 day per child , cost = x/4z;

For 7 children ,cost of food for 5 days = 5*7* x/4z= 35x/4z;

Ans:E
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Re: On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

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14 Sep 2017, 09:41
Bunuel wrote:
On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z?

A. 4z/(35x)

B. 140z/x

C. 140x/z

D. 28x/(5z)

E. 35x/(4z)

For the z-day hiking trip, the cost of food per child per day is (x/4)/z = x/(4z). Thus, the total cost of food for 7 children during a 5-day trip is x/(4z) * 7 * 5 = 35x/(4z).

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Re: On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

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09 Nov 2017, 13:45
4 children - x dollars - Z days

1 child -$$\frac{x}{4}$$ dollars - Z days

1 child -$$\frac{x}{4Z}$$ dollars - 1 day.

Rate of each child = $$\frac{x}{4z}$$ dollars/day.

For 7 children = $$\frac{7x}{4z}$$ dollars/day

For 5 days = $$\frac{35x}{4z}$$ dollars.

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Re: On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

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09 Nov 2017, 21:47
If we plugin nos we get 2 answers.
Let z=4 days,y=4 no of children and cost of food=16 dollars
Cost per child=16/4X4=1 dollar

2nd case =1X7X5=35

If we plugin above we get B & D as the correct answer.
My question to the experts is that can we get such kind of questions?
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Re: On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

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11 Nov 2017, 14:56
Bunuel wrote:
On a z day hiking trip, 4 children consumed food costing x dollars. For the same food costs per child per day, what would be the total cost of food consumed by 7 children during a 5 day hiking trip in terms of x and z?

A. 4z/(35x)

B. 140z/x

C. 140x/z

D. 28x/(5z)

E. 35x/(4z)

say, cost = c

4z / x = (7*5) / c

or, c = 35x / 4z

thanks
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Posts: 78
Location: Singapore
Concentration: Finance, General Management
GMAT 1: 620 Q46 V30
Re: On a z day hiking trip, 4 children consumed food costing x dollars.  [#permalink]

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26 Nov 2017, 04:48
4 children consumed food worth x amt of money for z days.

7 children would consume (7 * x/4) for z days.
For a 5 day hiking trip, they would consume (5/z * 7x/4) = 35x/4z

Option C.
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Re: On a z day hiking trip, 4 children consumed food costing x dollars. &nbs [#permalink] 26 Nov 2017, 04:48
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