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Turkish
Among a population of 30,000 people, 45 percent live within 10 miles of their workplace, 78 percent live inside the city limits of Town T, and 33 percent live both within 10 miles of their workplace and inside the city limits of Town T. If 1 person is to be randomly selected from the 30,000 people, what is the probability that the person lives within 10 miles of their workplace but NOT inside the city limits of Town T?

(A) 3/25
(B) 3/10
(C) 33/100
(D) 12/25
(E) 9/20

30,000 people
live within 10 miles: 30000(0.45) = 13,500
Live in city limits: 30000(0.78) = 23,400
Both: 30,000(0.33) = 9,900

People who live within 10 miles, but not in city limits 13,500 - 9,900 = 3,600

Probability of people who live within 10 miles, but not in city limits: 3,600/30,000 = 3/25

You do not need to really solve for the amount of people who live in city limits (78% of 30,000), I just did.
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Deconstructing the Question
Let A = lives within 10 miles of work.
Let B = lives inside city limits.
Given:
\(P(A)=45\%\)
\(P(B)=78\%\)
\(P(A\cap B)=33\%\)

We want A but not B.

Step-by-step

Only A:
\(P(A\text{ only})=P(A)-P(A\cap B)\)
\(=45\%-33\%=12\%\)

Convert to fraction:
\(\frac{12}{100}=\frac{3}{25}\)

Answer: 3/25
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