paddy41
chetan2u
fc2262a
The square of an even number equals 6 less than 5 times the number. Which of the following is the square of the number?
A) 2 B) 3 C) 4 D) 6 E) 9
Follow rules as applicable here..
As for your question, choices itself give out answer..
You are looking for square of even number as ANSWER
Only 4 fits in
D
Algebraically..
Number=n\(n^2=5n-6.....n^2-5n+6=0....n^2-3n-2n+6=0.....(n-2)(n-3)=0\)
So n can be 2 or 3, but it is even so 2
Square of 2=4
D
Dear chetan2u,
in a different post I got the tip to always rephrase an "even number" with 2n.
Hence I got stuck at \(2n^2 - 5n + 3 = 0\)
Can you explain when to rephrase an "even number" as 2n and when as simply n?
Hey,
You could have taken the number as "2n" also and solved the question.

However, the equation written by you incorrect!

According to the question:
The square of an even number: \((2n)^2\)
Equals 6 less than 5 times the number : \(5*(2n) - 6\)
Thus, we will write
\((2n)^2 = 5*(2n) - 6\)
\(4n^2 - 10n + 6 = 0\)
\(2n^2 - 5n + 3 = 0\)
\(2n^2 - 2n - 3n + 3 = 0\)
\(2n (n -1) -3 ( n-1) = 0\)
\((n-1) (2n -3) = 0\)
Since n needs to be an integer, the value of n will be 1
And the even number will be \(2n = 2*1 = 2\) and the square of this number will be \(2^2 = 4\)
I hope this clears your doubt.

Regards,
Saquib
Quant Expert, e-GMAT