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pushpitkc
In the time taken by Morton to take 4 steps, Lindsey takes 5 steps. If Morton's three steps are equal to
Lindsey's four steps and Lindsey's speed is 7.5 miles/hour, what is Morton's(approximate) speed?

A. 6
B. 7
c. 8
D. 9
E. 10

Source: Experts Global

Let's get Morton's steps to same base... LCM of 3 and 4 is 12
Morton's 3 steps = L's 4...
So M's 3*4 or 12 =L's 4*4=16 steps...
But when M takes 4, L takes 5,
So when M takes 4*3, L takes 5*3
That is when K covers 15 steps, M covers 16 equivalent steps

Speed M: L =16:15...
If 7.5 is 15, 16 will be 16*7.5/15=8
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Not getting both the solutions. Could someone please expain in an easy way.
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Tm= Morton's time to take 1 steps
Tl= Lindsey's time to take 1 steps
Lm= Morton's step size
Ll= Lindsey's step size

(Tm/Tl)= 5/4 ------------1)
(Lm/Ll)=4/3 ------------2)
Your aim is to find Lm/Tm (Morton's speed)

Ll/Tl (Lindsey's speed ) is given
Hence, Morton's speed( Lm/Tm)= (16* Lindsey's speed) /15
=8
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Let time Morton uses to take a step be y and let that of Lindsey be x.

Morton will take 4y

Lindsey will take 5x.

We are told Morton 3 steps = Lindsey 4, therefore

3y = 4x

y = 4x/3

Which makes Morton's time be

16x/3

If Morton app speed is a then ratio of their speeds will be

5x ÷ 16x/3 = 7.5/a

15/16 = 7.5/a

a = 8.

Posted from my mobile device
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Not getting both the solutions. Could someone please expain in an easy way.
­Simple way to read this is
L/S=5/4
since M's 3 steps =L's 4 steps , then ideally L's speed should be slowed down by 3/4,
implying L's new speed is 5*3/4=15/4
new ratio of L/s=(15/4)/4=(7.5/x), x=8
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Breaking down the problem to a form that's easier for us to play with ->

speed = distance/time
speed = (distance covered in 1 step = d) * (# of steps/ unit time = r). here's unit time is given in 1 hour

variables: Lindsey's and Morton's distance per step: d1 and d2; # of steps per hr: r1 and r2


Given: d2 = 4/3*d1 and r2 = 4/5*r1; Lindsey's speed = 7.5 miles/hr = d1*r1

Therefore, Morton's speed = d2*r2 = 4/3(d1)*4/5(r1) = 16/15*7.5 miles/hr = 8 miles/hr
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Bunuel Could you please share links to similar questions like this?
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Bunuel Could you please share links to similar questions like this?

Similar questions to practice:
https://gmatclub.com/forum/a-predator-i ... 81396.html (GMAT Club Tests)
https://gmatclub.com/forum/m-poirot-and ... 74656.html
https://gmatclub.com/forum/an-absent-mi ... 04469.html

Hope it helps.
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thanks for the solution. Its very simple to solve
thelastskybender
Tm= Morton's time to take 1 steps
Tl= Lindsey's time to take 1 steps
Lm= Morton's step size
Ll= Lindsey's step size

(Tm/Tl)= 5/4 ------------1)
(Lm/Ll)=4/3 ------------2)
Your aim is to find Lm/Tm (Morton's speed)

Ll/Tl (Lindsey's speed ) is given
Hence, Morton's speed( Lm/Tm)= (16* Lindsey's speed) /15
=8
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