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25 Jan 2018, 21:12
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:46) correct
31%
(02:02)
wrong
based on 131
sessions
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The probability of picking a boy in a class is \(\frac{1}{3}\). If two boys are removed from the class, the probability of picking a boy in the class goes down to \(\frac{5}{16}\). What is the number of boys in the class?
(A) 20
(B) 22
(C) 32
(D) 34
(E) Data insufficient
New question
source - self
(A) 20
(B) 22
(C) 32
(D) 34
(E) Data insufficient
New question
source - self
25 Jan 2018, 21:53
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chetan2u
let x be boys so total class 3x
now x-2 are boys so total are 3x-2
(x-2)/ (3x-2) = 5/16
16x-32 = 15x -10
16x-15x = 32-10
x=22
IMO B ??
26 Jan 2018, 04:27
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Let the total number of students in the class be 'T' and,
the number of boys among them be 'B'.
Therefore, probability of picking a boy = B/T = 1/3 ...(1)
If two boys are removed from the class, the probability of picking a boy = (B-2)/(T-2) = 5/16 ...(2)
Solving the two equations we get B = 22
Ans B
the number of boys among them be 'B'.
Therefore, probability of picking a boy = B/T = 1/3 ...(1)
If two boys are removed from the class, the probability of picking a boy = (B-2)/(T-2) = 5/16 ...(2)
Solving the two equations we get B = 22
Ans B
