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As per my understanding, 600 miles per hour , hence we can see that in an hour i.e 60 mins , it is travelling in a speed of 600miles ,
so 600/60 = 10
30 miles , 30/10 = 3 . Time right now , 4:58 + 3 = 5.01 ETA .

QA : B

Waiting for your QA Bunuel
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speed = 600 mph
distance = 30 miles
so, time = distance/speed = 30 miles/600mph=1/20 hours
1/20 hours = 3 minutes [(1/20)*60 min]
4:58 + 3 minutes = 5:01 pm

answer: B
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Time=\(\frac{Distance}{Speed}\)= \(\frac{30}{600}\)= \(\frac{1}{20}\) or \(\frac{1}{20}\)*60= 3 mins

4:58 + 3 minutes = 5:01 pm

Answer: B.
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first, convert the time unit to minutes instead of hours: 1 hour = 60 mins
R: D/T
R: (600 Miles/hour )/60 mins = 10
If T= 3 mins, what is T ? T= D/R ===> T= 30 miles/10= 3
Time = 4:58 + 3 mins : 5:01 (B)
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Bunuel
A plane traveling 600 miles per hour is 30 miles from Kennedy Airport at 4:58 p.m. At what time will it arrive at the airport?

(A) 5:00 p.m.

(B) 5:01 p.m.

(C) 5:02 p.m.

(D) 5:03 p.m.

(E) 5:20 p.m.

It will take the plane 30/600 = 1/20 hours = 3 minutes to get to Kennedy Airport. So the plane will arrive at 5:01 pm.

Answer: B
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Bunuel
A plane traveling 600 miles per hour is 30 miles from Kennedy Airport at 4:58 p.m. At what time will it arrive at the airport?

(A) 5:00 p.m.

(B) 5:01 p.m.

(C) 5:02 p.m.

(D) 5:03 p.m.

(E) 5:20 p.m.
\(\frac{600mi}{1hr}=\frac{600mi}{60mins}=\frac{60mi}{6mins}=\frac{10mi}{1min}\)

The plane is 30 miles away. At 10 miles per minute, it will cover that distance in 3 minutes.

Answer B
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Bunuel
A plane traveling 600 miles per hour is 30 miles from Kennedy Airport at 4:58 p.m. At what time will it arrive at the airport?

(A) 5:00 p.m.

(B) 5:01 p.m.

(C) 5:02 p.m.

(D) 5:03 p.m.

(E) 5:20 p.m.

600mph = 10mpm

So, Time required is 30/10 = 3 min

So, the Aircraft will land at (B) 5:01 p.m
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