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18 Sep 2018, 05:09
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
71% (02:40) correct
29%
(02:49)
wrong
based on 281
sessions
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A policeman chases a thief at a speed of 27kmph and catches him after 1 minute and 36 seconds. If the distance between the Policeman and the thief was 240 meters initially, What's the speed of the thief?
1) 6Kmph
2) 9Kmph
3) 12Kmph
4) 18Kmph
5) None of these
1) 6Kmph
2) 9Kmph
3) 12Kmph
4) 18Kmph
5) None of these
Afc0892
OA: D
\((V_{Policeman}-V_{Thief})* Time = Distance \quad b/w \quad Two\)
\((27-V_{Thief})* (\frac{1}{60}+\frac{36}{60*60}) = \frac{240}{1000}\)
\((27-V_{Thief})* (\frac{96}{60*60}) = \frac{240}{1000}\)
\((27-V_{Thief})* (\frac{96}{3600}) = \frac{24}{100}\)
\((27-V_{Thief})= \frac{24}{100}*\frac{3600}{96}\)
\((27-V_{Thief})= \frac{24*36}{96}=9\)
\(27-V_{Thief} = 9, V_{Thief}= 27-9= 18\) Km\hr
18 Sep 2018, 05:46
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Afc0892
Two ways..
Speed of policeman = 27kmph=27000/3600=7.5mps
So the policeman would travel 7.5*(60+36)=96*15/2=48*15=720
But policeman had to just cover 240 m, so remaining 720-240=480 is the distance thief ran in (60+36)secs so speed =480/96=5mps=5*3600/1000=18kmph
OR
Let the speed of thief be s, so relative speed =(27-x)kmph=(27-x)*1000/3600 mps
Therefore distance =speed *time
240=96*(27-x)*10/36
\(27-x=240*\frac{36}{10*96}=\frac{36}{4}=9......x=27-9=18\)
D
