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26 Sep 2018, 06:47
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:01) correct
19%
(01:08)
wrong
based on 1084
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
Line.PNG [ 7.43 KiB | Viewed 15849 times ]
(A) |x|≤2
(B) |x|≤4
(C) |x-2|≤2
(D) |x-1|≤3
(E) |x+1|≤3
Updated on: 04 Dec 2018, 03:48
Originally posted by GMATBusters on 26 Sep 2018, 08:04.
Last edited by GMATBusters on 04 Dec 2018, 03:48, edited 1 time in total.
Last edited by GMATBusters on 04 Dec 2018, 03:48, edited 1 time in total.
Edited a typo
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This is a very nice question to test the inequality concept
Steps to solve:
1) Plot the midpoint (a) of the solution set on the number line:
here the midpoint, a = (-4+2)/2 = -1
2) Find the distance (b unit) of either end points from the mid point :
here the distance, b = 2-(-1) = -1+4 = 3
3) Insert the appropriate sign of inequality between |x-a| and b:
Here , putting a and b, we get |x-(-1)|≤3
hence, the Required inequality is |x+1|≤3
Answer = E
Steps to solve:
1) Plot the midpoint (a) of the solution set on the number line:
here the midpoint, a = (-4+2)/2 = -1
2) Find the distance (b unit) of either end points from the mid point :
here the distance, b = 2-(-1) = -1+4 = 3
3) Insert the appropriate sign of inequality between |x-a| and b:
Here , putting a and b, we get |x-(-1)|≤3
hence, the Required inequality is |x+1|≤3
Answer = E
29 Nov 2018, 02:56
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Princ
Looking at the number line, we can say that the answer must be -4 ≤ x ≤ 2
Use property : If | x - a | ≤ b then - b ≤ x - a ≤ b
Applying this to option (E), we get the following:
-3 ≤ x+1 ≤3
Solving,
Adding (- 1) on both sides,
=> -3-1 ≤ x +1 -1 ≤ 3-1
=> -4 ≤ x ≤ 2
(The answer
) 
