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Bunuel
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Bunuel
If x, y, and z are consecutive odd integers, which of the following must be odd?

A. x + 2y + 3z
B. xyz
C. 2xyz
D. x(y + z)
E. (x + 1)(z - y)

For all given options we get is an even no. except for option B ... where all odd integers give an odd integer..
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The answer comes from the elimination method of the option.
The multiplication of two odd number always produces an odd number.
so the answer would be xyz.
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