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Archit3110
Bunuel
For how many positive integers, x, is it true that x^3 ≤ 3x?

A. None
B. One
C. Two
D. Four
E. More than four


x^3 ≤ 3x
or x^2<=3

at x=1 only it will stand out to be true .. IMO B

why not 0
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Bunuel
For how many positive integers, x, is it true that x^3 ≤ 3x?

A. None
B. One
C. Two
D. Four
E. More than four


x^3 ≤ 3x
or x^2<=3

at x=1 only it will stand out to be true .. IMO B

why not 0

“0” is not a positive integer. Positive integers start from 1 and so on. Hope this helps :)

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Archit3110
Bunuel
For how many positive integers, x, is it true that x^3 ≤ 3x?

A. None
B. One
C. Two
D. Four
E. More than four


x^3 ≤ 3x
or x^2<=3

at x=1 only it will stand out to be true .. IMO B

why not 0

We consider 0 as a "non-negative" integer but it does not belong to the group of "positive integers". :)
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Bunuel
For how many positive integers, x, is it true that x^3 ≤ 3x?

A. None
B. One
C. Two
D. Four
E. More than four

If x = 1, 1 ≤ 3

If x = 2, 8 is not less than 6.

If x = 3, 27 is not less than 9.

As we can see, as the value of x increases, x^3 will be always greater than 3x. Thus, we see that only one positive integer (the integer 1) fits the given criteria.

Alternate Solution:

Because x is positive, we can divide each side of the inequality x^3 ≤ 3x by x:

x^2 ≤ 3

Since 2^2 = 4 > 3, and since increasing x will only make x^2 greater, we see that the only positive integer that satisfies the given inequality is 1.

Answer: B
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Archit3110
Bunuel
For how many positive integers, x, is it true that x^3 ≤ 3x?

A. None
B. One
C. Two
D. Four
E. More than four


x^3 ≤ 3x
or x^2<=3

at x=1 only it will stand out to be true .. IMO B

Posted from my mobile device
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