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tinytiger
P(Jack wins but Jill does not) = Total number of favorable outcomes / Total possible outcomes.


Total number of ways to select Jack but not Jill for 5 people = 8C3 (Jack and Jill are excluded from the pool; Jack must be selected, so we only need to pick 3 random persons out of the pool of 8 remaining candidates)
P(Jack wins but Jill does not) = 8C3 / 10C5 = 5/18 (Option E).


Why do you pick 3 and not 4 if it is a group of 5??
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tinytiger
P(Jack wins but Jill does not) = Total number of favorable outcomes / Total possible outcomes.


Total number of ways to select Jack but not Jill for 5 people = 8C3 (Jack and Jill are excluded from the pool; Jack must be selected, so we only need to pick 3 random persons out of the pool of 8 remaining candidates)
P(Jack wins but Jill does not) = 8C3 / 10C5 = 5/18 (Option E).


Why do you pick 3 and not 4 if it is a group of 5??

I think this might just be a typo. 8c3 / 10c5 doesn't come out to 5/18, but 8c4 / 10c5 does. That also makes sense given what's in the problem: you need to choose FOUR other people, aside from Jack, who will win bikes.
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Thanks for the spot, typo corrected for in my original post. Correct answer is to pick FOUR, not three (am avoiding the usage of numerals since I may have typed too quickly in my previous post).
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