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the other way of calculating the number of arrangements would be to calculate the number of arrangements for each of the scenarios.

1- The Boy and the girl are not selected

3C6*3C4 = 80

2 - The boy is selcted but the girl isn't

2C6*3C4 = 60

3- The girl was selected and the boy wasn't

3C6*2C4 = 120

120+60+80 = 260 Answer D
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In how many ways can the team of 3 boys and 3 girls be formed out of 7 boys and 5 girls if one particular boy and one particular girl can not be together in the team?

A) 926
B) 350
C) 340
D) 260
E) 200

Source: https://www.GMATinsight.com

Let, Boys are A B C D E F G and Girls are P Q R S T

and A and P can NOT be together

Method-1:

Favourable cases = Total ways of making team of 3 boys and 3 girls - Ways of making team of 3 boys and 3 girls such that A and P are together

i.e. Favourable teams = 7C3*5C3 - 6C2*4C2 = 35*10 - 15*6 = 350 - 90 = 260

Answer: Option D

Method-2:
A is NOT selected and P is selected - 6C3*4C2 = 20*5 = 120
P is NOT selected and A is selected - 6C2*4C3 = 15*4 = 60
A and P both are NOT selected - 6C3*4C3 = 20*4 = 80

Total ways = 120+60+80 = 260

Answer: Option D
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