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Abhi077
A football league consists of 800 total players, 65 percent of whom play on offense. If there are only offensive and defensive players in the league, how many defensive players would have to join for the defensive players to comprise at least 40 percent of the league?
A) 63
B) 64
C) 65
D) 66
E) 67


Another method..

65% means Offensive are \(800\frac{65}{100}=520\)..

The ONLY change is in the number of Defensive player, so offensive players will remain the same as 520..
Say the new total is x.
But if D are atleast 40%, O will be at the most 60%, that is O\(\leq{\frac{60}{100}*x\)=> \(520\leq{\frac{60}{100}*x\)=> \(x\geq{520*100/60}......x\geq{866.66}\)

The number cannot be a decimal, so take the decimal as complete or 867..
The new player added = 867-800=67

E
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Isn't the language of the question different? I mean how can someone deduce that this is the way this question has to be solved. By reading the question I never even thought of going this way. The thought that came to my mind was 35% is 280 , and 40% of league is 320. So 40 must be added to get atleast 40%.­
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There must have been some mistakes that you came to such inference

The question simply asked how much more defence players are needed so that it becomes 40% of all atleast.

cm291093
Isn't the language of the question different? I mean how can someone deduce that this is the way this question has to be solved. By reading the question I never even thought of going this way. The thought that came to my mind was 35% is 280 , and 40% of league is 320. So 40 must be added to get atleast 40%.­
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other explanations confused me a bit. Here's how I solved it-

Total 800,
Currently, offence- 520 (65%)
defence- 280 (35%)

when the defence will raise up to 40%, the total will also rise

Therefore, 520/280+x= 60/40 (when the defence will rise up to 40%, offence will stay the same number as before)

1040=840+3x
200=3x
x=66.66 (Note that "atleast" this number will be needed)
Hence, E-67 is the correct answer
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