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akurathi12
If 108 is a factor of N^{2} then which of the following could be the remainder when N is divided by 36?

I. o
II. 18
III. 6

A. I only
B. III only
C. I& II only
D. I,II& III
E. None of these

In simple words we need to make the value of N in a multiple of 36 . But first lets find what can be minimum value of N .

Minimum value has to be such that N SHOULD BE DIVIDED by 108 completely . 108 = 2^2 * 3^2 * 3 so for N to be N^2 it has to have one more 3 SO THAT IT CAN BE DIVIDED by 108 .

so N^2 = 2^2 * 3^2 * 3^2*K = 324K (where K is a no. which maintains the square value of N^2 Hence N becomes 18K (SQUARE ROOT OF 324K)
NOW N/36 =18K/36 gives us remiander 18 .

NOW this K has to have minimum pairs as 36 have in order to get divided by 36 . So 3^2 * 2k /2^2*3^2
WE OBSERVED THAT WE NEED ONE MORE 2 so that the N gets completely divided hence N= 3^2* 2^2 will become 36 .
and we get remainder zero . Option 6 cant be as N is minimum 18K.


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akurathi12
If 108 is a factor of N^{2} then which of the following could be the remainder when N is divided by 36?

I. o
II. 18
III. 6

A. I only
B. III only
C. I& II only
D. I,II& III
E. None of these
Solution:

Recall that the prime factors of a perfect square all have even exponents.

Since 108 = 4 x 27 = 2^2 x 3^3, the smallest value of N^2 is 2^2 x 3^4, and hence the smallest value of N is 2 x 3^2 = 18. Of course, N also could be any multiple of 18. If N = 18k where k is odd, then the remainder when N is divided by 36 is 18. If N = 18k where k is even, then the remainder when N is divided by 36 is 0. So the remainder could be either 0 or 18.

Answer: C
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Given that 108 is a factor of \(N^2\) and we need to find which of the following could be the remainder when integer N is divided by 36?

108 is a factor of \(N^2\)
=> \(N^2\) is a multiple of 108

108 = \(2^2 * 3^3\)
=> \(N^2\) is a multiple of \(2^2 * 3^3\)
Making \(2^2 * 3^3\) close to the next even power (\(2^2 * 3^4\))

=> \(N^2\) = \(2^2 * 3^4\) * \(k^2\) (where k is an integer)
=> N = \(2*3^2\)k = 18k

=> N can be
18*0 = 0
18*1 = 18
18*2 = 36
and so on

=> 0/36 remainder is 0
=> 18/36 remainder is 18
=> 36/36 remainder is 0

=> Possible values of remainders are 0 and 18

So, Answer will be C
Hope it helps!

Watch the following video to learn the Basics of Factors and Multiples

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akurathi12

If 108 is a factor of N^{2} then which of the following could be the remainder when N is divided by 36?

I. o
II. 18
III. 6

A. I only
B. III only
C. I& II only
D. I,II& III
E. None of these

\(108 = 2^2*3^3\)

N = 2*3^2*x = 18x

Case 1: N = 36
The remainder when N is divided by 36 = 0

Case 2: N = 18
The remainder when N is divided by 36 = 18

N/36 = 18x/36 = x/2: The remainder when N is divided by 36 is 0 when x is even and the remainder when N is divided by 36 is 18 when x is odd

IMO C
akurathi12

If 108 is a factor of N^{2} then which of the following could be the remainder when N is divided by 36?

I. o
II. 18
III. 6

A. I only
B. III only
C. I& II only
D. I,II& III
E. None of these
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