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indu1954
Joined: 02 Nov 2017
Last visit: 23 Feb 2020
Posts: 29
Given Kudos: 22
Location: India
Schools: UVA Darden Tepper Babson '21 Johnson '21 Rotman '21 Booth '22
GPA: 3.87
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
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41% (01:59) correct
59%
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wrong
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In the coordinate plane there is the area of the region shaded surrounded by 3 inequalities. Which of the following options can be these inequalities?
1) \(x>0\)
2) \(y>0\)
3) \(y<-3x+8\)
4) \(y>(\frac{1}{2})x+4\)
5) \(y>(-\frac{1}{2})x+4\)
A. 1), 3), 5)
B. 1), 3), 4)
C. 2), 3), 5)
D. 2), 3), 4)
E. 2), 4), 5)
1) \(x>0\)
2) \(y>0\)
3) \(y<-3x+8\)
4) \(y>(\frac{1}{2})x+4\)
5) \(y>(-\frac{1}{2})x+4\)
A. 1), 3), 5)
B. 1), 3), 4)
C. 2), 3), 5)
D. 2), 3), 4)
E. 2), 4), 5)
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23 Mar 2019, 22:18
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indu1954
Hi..
In very simple terms,
You should note that the area is surrounded by three straight lines..
So if you substitute the inequality sign(< and >) with equality sign (=) in all 5 options, you should be able to get equation of these lines....
The next thing you can say that the two lines apart from y axis are having negative slope, because y and x have opposite effects, one increases the other decreases.
So the options that have negative coefficient of X while positive of y can be the equation of line..
Choice 3 and 5 have negative slope given by coefficients of x, -3 and -1/2.
Now we are left with the third side ..
So on y_axis, X is always 0, so x=0 is the third side, so 1,3,5
A
Of course if you want to get a bit more on theory , you can decide on the inequality sign < and > in option 3 and 5. But here you can answer without getting into any other details
24 Jul 2025, 02:21
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