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08 May 2019, 00:16
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In 40 seconds, a mountain biker travels 230 feet. What is her speed in miles per hour? (Note: 1 mile = 5280 feet)
A. \(\frac{230*60*60}{40*5280}\)
B. \(\frac{230*5280}{40*60*60}\)
C. \(\frac{40*60*60}{230*5280}\)
D. \(\frac{40*60*60*230}{5280}\)
E. \(\frac{40*60*60*5280}{230}\)
A. \(\frac{230*60*60}{40*5280}\)
B. \(\frac{230*5280}{40*60*60}\)
C. \(\frac{40*60*60}{230*5280}\)
D. \(\frac{40*60*60*230}{5280}\)
E. \(\frac{40*60*60*5280}{230}\)
saurabh9gupta
Joined: 10 Jan 2013
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08 May 2019, 00:40
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My approach-
Speed = Distance/ Time
therefore speed = 230 feet/40 sec
1mile = 5280 feet
therefore 1 feet = 1/5280 mile
1 hour = 60 * 60 sec
1 sec = 1/(60*60) hr
therefore
speed =(230 * 1/5280) miles/ (40 * 1/60*60) hrs
A
Speed = Distance/ Time
therefore speed = 230 feet/40 sec
1mile = 5280 feet
therefore 1 feet = 1/5280 mile
1 hour = 60 * 60 sec
1 sec = 1/(60*60) hr
therefore
speed =(230 * 1/5280) miles/ (40 * 1/60*60) hrs
A
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14 May 2019, 04:19
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Bunuel
D=RT ----> R=\(\frac{D}{T}\)
R = \(\frac{230ft}{40sec}\)
Convert to Miles/Hour.
To convert ft to Miles, divide by 5280.
To convert seconds to hours, multiply by 60*60
\(\frac{230ft}{40sec}\) * \(\frac{60*60}{5280}\) = \(\frac{60*60*230}{5280*40}\)
