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Time taken by a person to complete 1 job = 120

Work done by a person in 1 day = 1/120

Work done on 2nd day by 2 persons of same efficiency = 1/120 + 2/120 = 3/120

Work done on 3rd day by 3 persons . of same efficiency = 1/120 + 2/120 + 3/120 = 6/120

Work done on nth day by n persons of same efficiency = (1+2+3+4....... + n)/120

1 Job is completed on nth day. So the work done will be equal to 1:

(1+2+3+4....... + n)/120 = 1

n(n+1)/2 = 120 ( Sum of 1st n natural numbers = n(n+1)/2 )

Substituting the values from the options, we'll get n=15

The correct answer is C
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