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Bunuel
In a class 40% of the students enrolled for Math and 70% enrolled for Economics. If 15% of the students enrolled for both Math and Economics, what % of the students of the class did not enroll for either of the two subjects?

A. 0%
B. 5%
C. 15%
D. 25%
E. 35%

Let’s assume there are 100 students. Letting N = the number of students not enrolled in either of the two subjects, we can then create the equation:

100 = 40 + 70 - 15 + N

100 = 95 + N

5 = N

Thus, we have 5/100, or 5%, of the students that did not enroll in either of the two subjects.

Answer: B
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- Suppose, 280 is the actual number of all enrolled students.
- Number of students to be appear for Mathematics is 40% of 280 i.e. 0.4*280= 112
- Number of students to be appear for Economics is 70% of 280 i.e. 0.7*280= 196
- Number of students to be appear for both the subjects is 15% of 280 i.e 0.15*280 = 42, these students appear twice that’s why should be counted only once, thus;
- The actual number of students appearing for either of the two subjects = 112+196-42= 266
- Number of students who didn’t choose either of the two subjects = 280-266 = 14
- Percentage of students who didn’t choose either of the two subjects = (14/280)*100 = 5%

Note: 280 is the LCM of 40 & 70

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