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Bunuel
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Albert was driving on a straight highway, from Edenborough to Megiddo, 18 Dec 2019, 03:33
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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25% (medium)

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81% (02:38) correct 19% (02:24) wrong based on 237 sessions

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Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?

A. 80
B. 85
C. 90
D. 95
E. 100

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B
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Albert was driving on a straight highway, from Edenborough to Megiddo, 18 Dec 2019, 05:44
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Lets say Beatrice met Albert at \(d\) miles from Megiddo

Beatrice traveling at \(x\) mph covers these \(d\) miles in \(2\) hours while Albert traveling at \(60mph\) covers the same \(d\) miles in \(2\) hours and \(50\) minutes or \(2\frac{5}{6}=\frac{17}{6} hours\)

\(60*\frac{17}{6}=d\)
\(x*2=d\)

Therefore, \(60*\frac{17}{6}=2x\)

\(x=85mph\)

Answer is (B)
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Albert was driving on a straight highway, from Edenborough to Megiddo, 19 Dec 2019, 05:56
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Bunuel
Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?

A. 80
B. 85
C. 90
D. 95
E. 100
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B to X took 15:20 - 13:20 = 2 hrs
A to X took 16:10 - 13:20 = 2 hours + 50 mins = 2+5/6 = 17/6 hrs

distance = rate * time
b's rate * 2hrs = d
a's rate * 17/6hrs = d
b's rate * 2hrs = a's rate * 17/6hrs, 2b = 60*17/6, b=85

Ans (B)
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Albert was driving on a straight highway, from Edenborough to Megiddo, 19 Dec 2019, 10:59
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first using info of Albert find d=
total time taken by Albert to reach Megiddo = 2 Hrs : 50 mins or say ; 2+ 50/60 ; 17/6 hrs

so distance = 17/6 * 60 = 170 miles
time for Beatrice = 2 hrs
her speed = 170/2 ; 85 mph
IMO B


Bunuel
Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?

A. 80
B. 85
C. 90
D. 95
E. 100

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Albert was driving on a straight highway, from Edenborough to Megiddo, 23 Dec 2019, 00:48
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Distance = speed * time.

Distance is constant so speed is inversely proportional to time.
Time taken by Beatrice = 2 hours = 120 minutes
Time taken by Albert = 2 hours 50 min = 170 minutes

Speed of Albert = 60 mph
Let speed of Beatrice = S

Now, \(\frac{S}{60} = \frac{170}{120}\)
From here, we get S = 85.

OA - B
Bunuel
Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?

A. 80
B. 85
C. 90
D. 95
E. 100

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Albert was driving on a straight highway, from Edenborough to Megiddo, 23 Dec 2019, 21:55
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Bunuel
Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?

A. 80
B. 85
C. 90
D. 95
E. 100

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When Betrice(2) passed albert(1), remaining distance for both of them will be same
Speed2*t2=S1*t1
S2*120=60*170
S2=85mph
B:)
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Albert was driving on a straight highway, from Edenborough to Megiddo, 26 Dec 2019, 21:15
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Bunuel
Albert was driving on a straight highway, from Edenborough to Megiddo, at 60 mph. Beatrice was driving faster than Albert, on the same highway, in the same direction. She started behind Albert. She passed Albert at 1:20 pm. At 3:20 pm, Beatrice arrived at Megiddo, and Albert arrived 50 minutes later, at 4:10 pm. Assume both drivers kept up constant speeds without stops. What was Beatrice's speed, in mph?

A. 80
B. 85
C. 90
D. 95
E. 100

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We see that Beatrice drove for 2 hours after catching up with Albert and passing him. Meanwhile, for the same distance, Albert had to drive 2 hours and 50 minutes at 60 mph. Therefore, the distance from the point where Beatrice caught up with Albert and passed him to Megiddo is (2 + 50/60) x 60 = 120 + 50 = 170 miles. Therefore, Beatrice’s speed is 170/2 = 85 mph.

Answer: B
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Albert was driving on a straight highway, from Edenborough to Megiddo, 27 Jan 2026, 14:45
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Deconstructing the Question
This problem describes two drivers covering the same distance (from the passing point to the destination), but in different amounts of time.
When distance is constant, Speed and Time are inversely proportional.

  • Passing Point Time: 1:20 pm
  • Albert's Speed (\(R_A\)): 60 mph
  • Goal: Find Beatrice's Speed (\(R_B\)).

Step 1: Calculate the Time taken for the remaining trip
We only care about the segment from the passing point (1:20 pm) to Megiddo.

Beatrice's Time (\(T_B\)):
Starts at 1:20 pm, arrives at 3:20 pm.
\(T_B = 2 \text{ hours} = 120 \text{ minutes}\)

Albert's Time (\(T_A\)):
Starts at 1:20 pm (the moment he is passed), arrives at 4:10 pm.
\(T_A = 2 \text{ hours } 50 \text{ minutes} = 120 + 50 = 170 \text{ minutes}\)

Step 2: Use the Inverse Ratio Formula
Since Distance is constant:
\(\frac{R_B}{R_A} = \frac{T_A}{T_B}\)

Substitute the known values:
\(\frac{R_B}{60} = \frac{170}{120}\)

Step 3: Solve for Beatrice's Speed
Simplify the fraction:
\(\frac{R_B}{60} = \frac{17}{12}\)

Multiply by 60:
\(R_B = 60 \times \frac{17}{12}\)
\(R_B = 5 \times 17\)
\(R_B = 85 \text{ mph}\)

Answer: B
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Albert was driving on a straight highway, from Edenborough to Megiddo, 05 Feb 2026, 11:47
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Albert speed = 60
Albert time = 2 hours + 50 minutes which is 170 mins or 17/6 hours
Albert total distance = 60*17/6 = 170 miles

Beatrice speed = 60+ x
Beatrice time = 2 hours
Distance = (60+x) *2 = 170
x = 25

Plug x back into Beatrice's speed. 60+25 =85
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