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24 Jan 2020, 02:53
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:07) correct
27%
(02:06)
wrong
based on 141
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A motorcyclist goes from city X to Y, a distance of 192Km, at an average speed of 32Kmph. Another man starts from city X by car, 2.5hrs after the motorcyclist and reaches city Y 0.5hr earlier. What is the ratio of the speed of the motorcyclist to that of the car?
A. 1:2
B. 1:3
C. 5:4
D. 2:1
E. 2:3
A. 1:2
B. 1:3
C. 5:4
D. 2:1
E. 2:3
firas92
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24 Jan 2020, 03:10
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Time taken by motorcyclist = 192/32 = 6 hours
Lets say the motorcyclist starts at 12pm and reaches at 6pm
This means that the car starts at 2:30pm and reaches at 5:30pm which is 3 hours
So the speed of the car is 192/3 = 64kmph
Ratio of speed of motorcyclist to car is 32/64 = 1/2
Answer is (A)
Posted from my mobile device
Lets say the motorcyclist starts at 12pm and reaches at 6pm
This means that the car starts at 2:30pm and reaches at 5:30pm which is 3 hours
So the speed of the car is 192/3 = 64kmph
Ratio of speed of motorcyclist to car is 32/64 = 1/2
Answer is (A)
Posted from my mobile device
Lakshyamanchester
Joined: 13 Nov 2019
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Concentration: Finance, Marketing
Schools: Darden '22
24 Jan 2020, 03:22
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The answers is A.
Time taken by motorcyclist= 192/32= 6hrs
Then, it is given that the car driver reaches 0.5hrs before motorcyclist, therefore 6-0.5=5.5hrs.
Then further, it starts 2.5hrs after the motorcyclist = 5.5-2.5= 3hrs.
It takes car 3hrs to complete the distance of 192.
Then its speed be 192/3=64kmph
Ratio would be 32/64=1:2.
Posted from my mobile device
Time taken by motorcyclist= 192/32= 6hrs
Then, it is given that the car driver reaches 0.5hrs before motorcyclist, therefore 6-0.5=5.5hrs.
Then further, it starts 2.5hrs after the motorcyclist = 5.5-2.5= 3hrs.
It takes car 3hrs to complete the distance of 192.
Then its speed be 192/3=64kmph
Ratio would be 32/64=1:2.
Posted from my mobile device
