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Bunuel
If p is a positive integer, for what minimum value of p is \(7 * 10^p + 4p\) divisible by 9?

A. 3
B. 5
C. 11
D. 14
E. 19

For an integer to be divisible by 9, the sum of digits of the integer should be divisible by 9

A. 3
\(7 * 10^p + 4p\) = 7000+12=7012

7+0+1+2 = 10 - Not divisible by 9

B. 5
\(7 * 10^p + 4p\) = 700000+20=700020

7+0+0+0+2+0 = 9 - Divisible by 9

Answer is (B)
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Bunuel
If p is a positive integer, for what minimum value of p is \(7 * 10^p + 4p\) divisible by 9?

A. 3
B. 5
C. 11
D. 14
E. 19

divisibility rule of 9 ; sum of digits has to be 9
in this case P has to be 5 ;
IMO B
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Bunuel
If p is a positive integer, for what minimum value of p is \(7 * 10^p + 4p\) divisible by 9?

A. 3
B. 5
C. 11
D. 14
E. 19

We need the sum of the digits of x 10^p + 4p to be a multiple of 9. Since we are looking for a minimum value of p, let’s check the values in the given choices from the smallest to the largest.

A. 3

7 x 10^3 + 4(3) = 7000 + 12 = 7012

The sum of the digits is 10, which is not a multiple of 9, so A is not the correct answer.

B. 5

7 x 10^5 + 4(5) = 700,000 + 20 = 700,020

Since the sum of the digits is 9, B is the correct answer.

Answer: B

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Bunuel
If p is a positive integer, for what minimum value of p is \(7 * 10^p + 4p\) divisible by 9?

A. 3
B. 5
C. 11
D. 14
E. 19

The fastest way to solve this problem in under 1 minute is to test the answers. For this, we will need to know some basic rules of divisibility. A number is dividisble by 9 if the SUM of its DIGITS is divisible by 9.

Since we are asked to find the minimum value, I will start by testing the lowest numbers first.

Let's try option A.
7 * 10^3 + 4*3 = 7000 + 12
The sum of the DIGITS is 10 (7+1+2)
10 is not divisible by 9.
Let's move on to the next answer option.

Let's try option B.
7 * 10^5 + 4*5 = 700,000 + 20
The sum of the DIGITS is 9 (7+2)
9 is obviously divisible by 9.

Correct answer!
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Bunuel
If p is a positive integer, for what minimum value of p is \(7 * 10^p + 4p\) divisible by 9?

A. 3
B. 5
C. 11
D. 14
E. 19
\(7 * 10^p\) will result in 70........... (No of 0's will depend on the value of p and the same is irrelevant as sum will be 7 irrespective of the value of p)

Thus, for \(7 * 10^p + 4p\) to be divisible by 9 the value of \(7 * 10^p + 4p\) must be divisible by 9...

Again we know, the sum of \(7 * 10\) is 7...

So, The deciding factor is the value of \(4p\)

Now, check the options...

(A) \(7*10^3 + 4*3 = 7+12 =19\) (Not divisible by 9)
(B) \(7*10^5 + 4*5 = 7+20 = 27\) (Divisible by 9) (Answer)

If you want you can check and reconfirm the option...
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why not 14 then ? 7+5+6 = 18
firas92


For an integer to be divisible by 9, the sum of digits of the integer should be divisible by 9

A. 3
\(7 * 10^p + 4p\) = 7000+12=7012

7+0+1+2 = 10 - Not divisible by 9

B. 5
\(7 * 10^p + 4p\) = 700000+20=700020

7+0+0+0+2+0 = 9 - Divisible by 9

Answer is (B)
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bcecharly
why not 14 then ? 7+5+6 = 18


If p = 14, 7 * 10^p + 4p is alos divisible by 9 but it's not the minimum possible value of p:

If p is a positive integer, for what minimum value of p is \(7 * 10^p + 4p\) divisible by 9?
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