If a book has 252 pages, how many digits have been used to number the

Question

Competition Mode Question

If a book has 252 pages, how many digits have been used to number the pages?

A. 648
B. 650
C. 660
D. 661
E. 662

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GMATinsight · Answer

To answer the question, we need to calculate the total digits used in writing numbers from 1 to 252

Single Digit numbers = 9 (1 to 9)
So, Digits used in Single-digit numbers = 1*9 = 9

Two Digit numbers = 90 (10 to 99)
So, Digits used in Two digit numbers = 2*90 = 180

Three-digit Numbers = 153 (100 to 252)
So, Digits used in Three digit numbers = 3*153 = 459

Total Digits used = 9+180+459 = 648

Answer: Option A

shameekv1989 · Answer

Digits for pages 1-9 => 9
Digits used for pages 10-99 => 99-10+1 = 90*2 = 180
Digits used for pages 100-252 =. 252-100+1 = 153*3 = 459

Adding we get Total number of digits used to page the numbers = 648 - Answer - A

KarishmaB · Answer

The question asks us how many digits are used to write numbers from 1 to 252.

There are 252 units digits.
252 - 9 = 243 tens digits (because first 9 numbers don't have tens digits)
and 252 - 99 = 153 hundreds digits (because first 99 numbers don't have hundreds digits)

Total = 252 + 243 + 153 = 648

Answer (A)

exc4libur · Answer

1 digit pages: 1 to 9 = 9 numbers * 1 digit = 9
2 digit pages: 10 to 99 = 90 numbers * 2 digits = 180
3 digit pages: 100 to 252 = 153 numbers * 3 digits = 459
total digits: 459+180+9 = 648

Ans (A)

dhawalsachdeva · Answer

648

(252-100+1)*3 + (99-10+1)*2 +9

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ArunSharma12 · Answer

Numbering the pages and digits used for each section of pages

1- 9: 1*9 
10-99: 90*2
100-199: 100*3
200-249: 50*3
250-252: 3*3

Total Digits = 9 + 180 + 300 + 150 + 9 = 648

freedom128 · Answer

PAGE 1-9 --> 9 page*1=9 digits
PAGE 10-99 --> 90 page*2= 180 digits
PAGE 100-252 --> 153 page*3= 459 digits
Total digits that have been used to number the pages = 9 +180 +459 = 648

FINAL ANSWER IS (A) 648

Jawad001 · Answer

If a book has 252 pages, how many digits have been used to number the pages?

A. 648
B. 650
C. 660
D. 661
E. 662

From 1 to 9 , there are 9 digits
From 10 to 99 , there are 99-10+1 = 90 pages. Number of digits in 90 pages = 90*2 = 180.
From 10 to 99 , there are 252-100+1 = 153 pages. Number of digits in 153 pages = 153*3 = 459.
Total number of digits = 9 + 180 + 459 = 648
Answer:648(A)

lacktutor · Answer

If a book has 252 pages, how many digits have been used to number the pages?

—> from 1 to 9 —9 digits 
—> from 10 to 99 — 90*2 = 180 digits 
—> from 100 to 252 —153*3 = 459 digits

In total, 9+ 180 + 459= 648 digits

The answer is A.

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madgmat2019 · Answer

No.of digits from
1-9 = 9
10-99 = 90*2= 180
100-252 = 153*3= 459
Total no.of digits= 9+180+459=648

OA:A

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Archit3110 · Answer

total no of digits
0-9 ; 9 digits
from 
10-99 ; 90*2 ; 180 digits
from 100 to 252 ; 153*3 ; 459 digits
total 459+180+9 ; 648
IMO A

If a book has 252 pages, how many digits have been used to number the pages?

A. 648
B. 650
C. 660
D. 661
E. 662

unraveled · Answer

If a book has 252 pages, how many digits have been used to number the pages?

A. 648
B. 650
C. 660
D. 661
E. 662

Number of digits at ones place = 252
Number of digits at tens place = 252 - 9 = 243
Number of digits at hundreds lace = 252 - 99 = 153

Total = 252 + 243 + 153 = 648

Answer A.

Kinshook · Answer

1-9 -> 9 digits
10-99-> 3*90 = 180 digits
100-252-> 3*153 = 549 digits

Total digits used = 9 + 180 + 549 = 648

IMO A

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bumpbot · Answer

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If a book has 252 pages, how many digits have been used to number the

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If a book has 252 pages, how many digits have been used to number the

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