In the diagram above, triangle ADE is inscribed in square ABCD. If t

Question

GMATBusters’ Quant Quiz Question -6 https://gmatclub.com/forum/download/file.php?id=53488 In the diagram above, triangle CDE is inscribed in square ABCD. If the area of the triangle is 50, what is the perimeter of the square? A. 20 B. 32 C. 40 D. 48 E. 50 gc1.JPG

shameekv1989 · Answer

Area of triangle = \frac{1}{2}*CD*AC = 50 => CD*AC = 100

Since CD = AC (as they are sides of a square)

CD = AC = 10

Therefore Perimeter = 4*CD = 40 - Answer - C

Raxit85 · Answer

In the diagram above, triangle CDE is inscribed in square ABCD. If the area of the triangle is 50, what is the perimeter of the square?

Area of triangle CDE = 50, 
1/2 * CD * EO = 50 (if we assume point O, which is perpendicular, on CD)
So, CD * EO = 100 
CD = 10 and EO = 10 as EO is length of square.
So, length of square = 10 each. So perimeter of square = 40.

Ans. C

Kinshook · Answer

In the diagram above, triangle CDE is inscribed in square ABCD. If the area of the triangle is 50, what is the perimeter of the square? 
A. 20 
B. 32 
C. 40 
D. 48 
E. 50

Let the side of the square ABCD be x

Area of triangle CDE = 1/2 * CD * AC = x^2/2 = 50
x^2 = 100
x = 10

Perimeter of the square ABCD = 4*10 = 40

IMO C

monirhossain2nd · Answer

As ABCD is a square AB=BC=CD=DA=x
Assume a line EF, perpendicular to line CD 
Where EF=x
Now area of the triangle 1/2. EF.CD=50
 EF.CD=100
x2=100
x=10

So the perimeter of the square is, 4x=40

Ans. C

Danchar42 · Answer

In the diagram above, triangle CDE is inscribed in square ABCD. If the area of the triangle is 50, what is the perimeter of the square?
A. 20
B. 32
C. 40
D. 48
E. 50

The area of the triangle is 1/2 * b * h. in this case, the base and height also = the side of the square
50 = 1/2 (s) (s) --> s = 10 --> perimeter = 40 -->  answer is (c)

mohagar · Answer

we just need to use the formula of the trangle . 1/2 base * height . we get side so 4 * side is the answer 40

neharaj0001 · Answer

Option (C)40
Area of triangle
=b×h/2
=CD×CA/2 (height has same length as CA, base is CD)
=CD^2/2 (CA=CD since it's a square)
= 50
CD = sqrt(100) = 10
Perimeter=4×CD=40

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AnirudhaS · Answer

riangle CDE = \frac{1}{2}*base*altitude = 50 
 or, \frac{1}{2} * a * a = 50, 
or, a = 10

Therefore, 4a = 40

Answer: C

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In the diagram above, triangle ADE is inscribed in square ABCD. If t

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In the diagram above, triangle ADE is inscribed in square ABCD. If t

Prep Toolkit

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