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In the diagram above, triangle CDE is inscribed in square ABCD. If the area of the triangle is 50, what is the perimeter of the square?
A. 20
B. 32
C. 40
D. 48
E. 50

Let the side of the square ABCD be x

Area of triangle CDE = 1/2 * CD * AC = x^2/2 = 50
x^2 = 100
x = 10

Perimeter of the square ABCD = 4*10 = 40

IMO C
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As ABCD is a square AB=BC=CD=DA=x
Assume a line EF, perpendicular to line CD
Where EF=x
Now area of the triangle 1/2. EF.CD=50
EF.CD=100
x2=100
x=10

So the perimeter of the square is, 4x=40

Ans. C
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In the diagram above, triangle CDE is inscribed in square ABCD. If the area of the triangle is 50, what is the perimeter of the square?
A. 20
B. 32
C. 40
D. 48
E. 50


The area of the triangle is 1/2 * b * h. in this case, the base and height also = the side of the square
50 = 1/2 (s) (s) --> s = 10 --> perimeter = 40 --> answer is (c)
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we just need to use the formula of the trangle . 1/2 base * height . we get side so 4 * side is the answer 40
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Option (C)40
Area of triangle
=b×h/2
=CD×CA/2 (height has same length as CA, base is CD)
=CD^2/2 (CA=CD since it's a square)
= 50
CD = sqrt(100) = 10
Perimeter=4×CD=40

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\(\triangle CDE = \frac{1}{2}*base*altitude = 50\)
\(or, \frac{1}{2} * a * a = 50,\)
or, a = 10

Therefore, 4a = 40

Answer: C
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Hello from the GMAT Club BumpBot!

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