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12 Apr 2020, 02:24
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
47% (02:28) correct
53%
(02:30)
wrong
based on 188
sessions
History
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Two trains A and B start simultaneously in the opposite direction from two points P and Q and arrive at their destinations(Q and P) 16 and 9 hours respectively after their meeting each other. At what speed does the second train B travel if the first train travels at 120 kmph
A. 90 kmph
B. 200 kmph
C. 240 kmph
D. 160 kmph
E. 360 kmph
A. 90 kmph
B. 200 kmph
C. 240 kmph
D. 160 kmph
E. 360 kmph
12 Apr 2020, 05:04
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jackfr2
\(S_A/S_B = √(t_B/t_A)\)
\(120/S_B = √(9/16)\)
\(S_B = 160\)
Answer: Option D
General Discussion
12 Apr 2020, 03:29
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Distance covered by train A till both trains meet =\( L_A\)
Distance covered by train B till both trains meet =\( L_B\)
Speed of train A = \(V_A\)
Speed of train B = \(V_B\)
\(\frac{L_A}{v_A}\) = \(\frac{L_B}{v_B}\)
\(\frac{L_A}{L_B}\) = \(\frac{v_A}{v_B}\).......(1)
Given-
\(\frac{L_A}{v_B} = 9\).....(2)
\(\frac{L_B}{v_A} = 16\)....(3)
Divide (2) by (3)
\(\frac{L_A}{L_B} *\frac{v_A}{v_B} =\frac{ 9}{16}\)
\((\frac{v_A}{v_B})^2 = (\frac{3}{4})^2\)
\(\frac{v_A}{v_B}= \frac{3}{4}\)
\(\frac{120}{v_B} = \frac{3}{4}\)
\(v_B = 160\)
Distance covered by train B till both trains meet =\( L_B\)
Speed of train A = \(V_A\)
Speed of train B = \(V_B\)
\(\frac{L_A}{v_A}\) = \(\frac{L_B}{v_B}\)
\(\frac{L_A}{L_B}\) = \(\frac{v_A}{v_B}\).......(1)
Given-
\(\frac{L_A}{v_B} = 9\).....(2)
\(\frac{L_B}{v_A} = 16\)....(3)
Divide (2) by (3)
\(\frac{L_A}{L_B} *\frac{v_A}{v_B} =\frac{ 9}{16}\)
\((\frac{v_A}{v_B})^2 = (\frac{3}{4})^2\)
\(\frac{v_A}{v_B}= \frac{3}{4}\)
\(\frac{120}{v_B} = \frac{3}{4}\)
\(v_B = 160\)
jackfr2
