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Bunuel
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In a tournament, there are two groups of teams. Group A has 20 teams 20 Apr 2020, 05:12
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In a tournament, there are two groups of teams. Group A has 20 teams and Group B has 25 teams. The average (arithmetic mean) scores of teams in Group A and B are 20 and 25, respectively. The highest and lowest scores in Group A are 25 and 15, respectively and the highest and lowest scores in Group B are 32 and 24, respectively. What can be the minimum and maximum value of Groups B’s average scores, if 5 teams are transferred from Group A to Group B?

A. 22.5 and 25
B. 25 and 25
C. 70/3 and 25
D. 70/3 and 26
E. 70/3 and 30


Are You Up For the Challenge: 700 Level Questions
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C
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In a tournament, there are two groups of teams. Group A has 20 teams 20 Apr 2020, 09:15
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Bunuel
In a tournament, there are two groups of teams. Group A has 20 teams and Group B has 25 teams. The average (arithmetic mean) scores of teams in Group A and B are 20 and 25, respectively. The highest and lowest scores in Group A are 25 and 15, respectively and the highest and lowest scores in Group B are 32 and 24, respectively. What can be the minimum and maximum value of Groups B’s average scores, if 5 teams are transferred from Group A to Group B?

A. 22.5 and 25
B. 25 and 25
C. 700/3 and 25
D. 700/3 and 26
E. 700/3 and 30


Are You Up For the Challenge: 700 Level Questions
Show more

...................A......B
# of teams....20...25
Average........20...25

% teams are to be transferred from A to B..
Let A's teams score be 10 have highest score, that is 25 and remaining 10 have 15, the lowest.

MAX average of B after transfer..


All 5 have maximum possible, that is 25, so NEW average of B = \(\frac{25*25+25*5}{30}=25\)

MIN average of B after transfer..


All 5 have minimum possible, that is 15, so NEW average of B = \(\frac{25*25+15*5}{30}=\frac{25(25+3)}{30}=\frac{700}{3}\)

So Min and Max = 25 and 700/3

C
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In a tournament, there are two groups of teams. Group A has 20 teams 20 Apr 2020, 12:10
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chetan2u
Bunuel
In a tournament, there are two groups of teams. Group A has 20 teams and Group B has 25 teams. The average (arithmetic mean) scores of teams in Group A and B are 20 and 25, respectively. The highest and lowest scores in Group A are 25 and 15, respectively and the highest and lowest scores in Group B are 32 and 24, respectively. What can be the minimum and maximum value of Groups B’s average scores, if 5 teams are transferred from Group A to Group B?

A. 22.5 and 25
B. 25 and 25
C. 700/3 and 25
D. 700/3 and 26
E. 700/3 and 30


Are You Up For the Challenge: 700 Level Questions

...................A......B
# of teams....20...25
Average........20...25

% teams are to be transferred from A to B..
Let A's teams score be 10 have highest score, that is 25 and remaining 10 have 15, the lowest.

MAX average of B after transfer..


All 5 have maximum possible, that is 25, so NEW average of B = \(\frac{25*25+25*5}{30}=25\)

MIN average of B after transfer..


All 5 have minimum possible, that is 15, so NEW average of B = \(\frac{25*25+15*5}{30}=\frac{25(25+3)}{30}=\frac{700}{3}\)

So Min and Max = 25 and 700/3

C
Show more


I think the minimum should be 700/30 = 70/3 and not 700/3, options are also incorrect. Bunuel , please look into it
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In a tournament, there are two groups of teams. Group A has 20 teams 20 Apr 2020, 12:15
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Aviralft9
chetan2u
Bunuel
In a tournament, there are two groups of teams. Group A has 20 teams and Group B has 25 teams. The average (arithmetic mean) scores of teams in Group A and B are 20 and 25, respectively. The highest and lowest scores in Group A are 25 and 15, respectively and the highest and lowest scores in Group B are 32 and 24, respectively. What can be the minimum and maximum value of Groups B’s average scores, if 5 teams are transferred from Group A to Group B?

A. 22.5 and 25
B. 25 and 25
C. 700/3 and 25
D. 700/3 and 26
E. 700/3 and 30


Are You Up For the Challenge: 700 Level Questions

...................A......B
# of teams....20...25
Average........20...25

% teams are to be transferred from A to B..
Let A's teams score be 10 have highest score, that is 25 and remaining 10 have 15, the lowest.

MAX average of B after transfer..


All 5 have maximum possible, that is 25, so NEW average of B = \(\frac{25*25+25*5}{30}=25\)

MIN average of B after transfer..


All 5 have minimum possible, that is 15, so NEW average of B = \(\frac{25*25+15*5}{30}=\frac{25(25+3)}{30}=\frac{700}{3}\)

So Min and Max = 25 and 700/3

C


I think the minimum should be 700/30 = 70/3 and not 700/3, options are also incorrect. Bunuel , please look into it
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____________________
Fixed. Thank you.
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In a tournament, there are two groups of teams. Group A has 20 teams 28 Apr 2020, 04:41
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Bunuel
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chetan2u
Bunuel
In a tournament, there are two groups of teams. Group A has 20 teams and Group B has 25 teams. The average (arithmetic mean) scores of teams in Group A and B are 20 and 25, respectively. The highest and lowest scores in Group A are 25 and 15, respectively and the highest and lowest scores in Group B are 32 and 24, respectively. What can be the minimum and maximum value of Groups B’s average scores, if 5 teams are transferred from Group A to Group B?

A. 22.5 and 25
B. 25 and 25
C. 700/3 and 25
D. 700/3 and 26
E. 700/3 and 30


Are You Up For the Challenge: 700 Level Questions

...................A......B
# of teams....20...25
Average........20...25

% teams are to be transferred from A to B..
Let A's teams score be 10 have highest score, that is 25 and remaining 10 have 15, the lowest.

MAX average of B after transfer..


All 5 have maximum possible, that is 25, so NEW average of B = \(\frac{25*25+25*5}{30}=25\)

MIN average of B after transfer..


All 5 have minimum possible, that is 15, so NEW average of B = \(\frac{25*25+15*5}{30}=\frac{25(25+3)}{30}=\frac{700}{3}\)

So Min and Max = 25 and 700/3

C


I think the minimum should be 700/30 = 70/3 and not 700/3, options are also incorrect. Bunuel , please look into it
____________________
Fixed. Thank you.
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the question says highest so how can we take 25*5?? shouldnt it be 25 + 24*4??
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In a tournament, there are two groups of teams. Group A has 20 teams 20 Sep 2024, 15:15
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The highest value possible in group A is 25.
Imagine all 5 that came from group A to group B are 25 .
New total in group B = 30
Exsiting 25 teams had the average of 25 and new 5 came with a value 25 each.
hence the new total = (25*25 + 5*25)
nikitamaheshwari
Bunuel

Bunuel
In a tournament, there are two groups of teams. Group A has 20 teams and Group B has 25 teams. The average (arithmetic mean) scores of teams in Group A and B are 20 and 25, respectively. The highest and lowest scores in Group A are 25 and 15, respectively and the highest and lowest scores in Group B are 32 and 24, respectively. What can be the minimum and maximum value of Groups B’s average scores, if 5 teams are transferred from Group A to Group B?

A. 22.5 and 25
B. 25 and 25
C. 700/3 and 25
D. 700/3 and 26
E. 700/3 and 30


Are You Up For the Challenge: 700 Level Questions

...................A......B
# of teams....20...25
Average........20...25

% teams are to be transferred from A to B..
Let A's teams score be 10 have highest score, that is 25 and remaining 10 have 15, the lowest.

MAX average of B after transfer..


All 5 have maximum possible, that is 25, so NEW average of B = \(\frac{25*25+25*5}{30}=25\)

MIN average of B after transfer..


All 5 have minimum possible, that is 15, so NEW average of B = \(\frac{25*25+15*5}{30}=\frac{25(25+3)}{30}=\frac{700}{3}\)

So Min and Max = 25 and 700/3

C


I think the minimum should be 700/30 = 70/3 and not 700/3, options are also incorrect. Bunuel , please look into it
____________________
Fixed. Thank you.

the question says highest so how can we take 25*5?? shouldnt it be 25 + 24*4??
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